嘿,我想知道是否有可能从mysqli查询中获取一个值并在同一页面中使用它,如果可以的话,我该怎么做?
$sql2 = "select artistName from ARTIST";
$result2 = $conn->query($sql2);
if($result2->num_rows != 0){
echo "<p>Artist: <select artistname=\"artistName\">";
while ($val2 = $result2->fetch_assoc()) {
echo "<option value='$val2[artistName]'>$val2[artistName]</option>";
}
echo "</select></p>";
}
我正尝试在下面提出此请求:
$addArt = "update ARTIST set Aname='$fileName' where artistName='$val2[artistName]'";
其中文件名是任意文件
多个问题:
"<option value='$val2[artistName]'>$val2[artistName]</option>"
"update ARTIST set Aname='$fileName' where artistName='$val2[artistName]'"
与双引号和heredoc语法不同,特殊字符的变量和转义序列在单引号引起来的字符串中不会扩展。
参考:https://www.php.net/manual/en/language.types.string.php
"update ARTIST set Aname='$fileName' where artistName='$val2[artistName]'"
您需要小心获取值$val2[artistName]
,否则可能会导致SQL注入攻击