如果使用difflib.unified_diff时没有差异，我如何打印pass

Question

此代码将在使用 difflib 之前和之后进行比较，并打印差异，如果没有差异，我该如何打印差异？

import difflib
before = ['abc\n', 'def\n']
after = ['xyz\n', 'def\n']
for line in difflib.unified_diff(before, after):
   print (line)

我试着把它写成：

import difflib
before = ['abc\n', 'def\n']
after = ['xyz\n', 'def\n']
for line in difflib.unified_diff(before, after):
    x = len(line)
    if x == 0:
        print (line)
    else:
        print("no diff")

但它不起作用！

输入代码，打印出来

Answer 1

你只需要稍微重新安排一下你的逻辑。

试试这个，

import difflib

before = ['abc\n', 'def\n']
after = ['xyz\n', 'def\n']

diff = list(difflib.unified_diff(before, after))

if len(diff) == 0:
    print("no diff")
else:
    for line in diff:
        print(line)

首先运行 difflib 函数并检查长度。如果为零，则不打印 diff，但如果不是，则照常运行 for 循环。

Answer 2

尝试使用 ndiff ：https://docs.python.org/3/library/difflib.html#difflib.ndiff

你的解决方案很简单， 声明变量后，

diff = list(difflib.ndiff(before, after)

if not diff:
    print("It doesn't exist")