python pyz7r 压缩后解压时出现“不支持的功能”

Question

我正在尝试使用

pyz7r

Python模块来压缩我拥有的一些文件夹，我想要的是确保这些文件夹被压缩到存档中，如下所示：

Here are my folders.

SomeFolder.
  - File1.txt
  - File2.txt
AnotherOne
  - Wow.txt
  - IAmAFile.txt

I want the output after creating the 7z file and unzip it to be as the following:

UnzippedFolder
  SomeFolder.
    - File1.txt
    - File2.txt
  AnotherOne
    - Wow.txt
    - IAmAFile.txt

我听说过使用这个：

folders = ["./SomeFolder", "./AnotherOne"]

with py7zr.SevenZipFile("Zipped.7z", 'w') as archive:
    for folder in folders:
        print(f"Zipping {folder}....")
        archive.writeall(FOLDER)
        print("DONE!")

直到这里一切都很好，直到我尝试使用 7zip 程序解压缩文件夹时，它返回以下错误：

无法将文件打开为 [7z] 存档
不支持的功能

我不知道问题出在哪里。另外，我从未尝试过

writeall

（或从未为我工作过）功能，但据我所知，它执行的文件和文件夹顺序与我想要的相同。

如果有帮助的话，我使用的是 Windows 11。

Answer 1

import py7zr

folders = ["./SomeFolder", "./AnotherOne"]

with py7zr.SevenZipFile("Zipped.7z", 'w') as archive:
    for folder in folders:
        print(f"Zipping {folder}....")
        # Add the entire folder and its contents to the archive
        archive.writeall(folder, arcname=folder)
        print("DONE!")

# Now, when you extract the archive, it should have the desired structure.