二元树的最小公有祖先--递归解法。

问题描述 投票:0回答:1

这是一个leetcode问题。 https:/leetcode.comproblemslowest-common-ancestor-of-a-binary-tree.

我的代码在这里

class CommonAncestor:

    def traverse(self, root, A, B):

        if not root:
            return None

        return self.helper(root, A, B)

    def helper(self, node, A, B):
        print(node)
        if node:        

            left = self.helper(node.left, A, B)
            right = self.helper(node.right, A, B)

            if node.val == A or node.val == B:
                return node

            if left and right:
                return node
            elif left or right:
                return left or right
            else:
                return None

谁能解释一下为什么这段代码不能用?它在我的VS代码上运行得很完美,但它无法通过测试用例。我在这里创建了完全相同的树。

class TreeNode:

    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None


obj = CommonAncestor()

root = TreeNode(3)

root.left = TreeNode(5)
root.left.left = TreeNode(6)
root.left.right = TreeNode(2)
root.left.right.left = TreeNode(7)
root.left.right.right = TreeNode(4)

root.right = TreeNode(1)
root.right.left = TreeNode(0)
root.right.right = TreeNode(8)
root.right.right.left = None
root.right.right.right = None

我不知道这是否是leetcode特有的还是我的代码... 非常感谢

python recursion tree binary-tree
1个回答
0
投票

好吧,我想明白了... LeetCode的输入类型是TreeNode,而我的输入类型是int......

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