PostGis Polygon使用django进入传单地图

Question

我的问题是我不知道如何使用django将PostGIS中存储的多边形可视化为传单地图。

在模板中我用它来绘制点：

  <script type="text/javascript">

      function map_init(map, options) {
        {% for each_model in loca %}

          var lon =   {{each_model.location.x}}
          var lat =   {{each_model.location.y}}


          map.setView([lat, lon], 2);

          L.marker([lat, lon]).bindPopup("{{each_model.name}}").addTo(map)

          {% endfor %}
          // get point lat and lon

          // zoom to point & add it to map
        ;
      }

  </script>

models.朋友

from __future__ import unicode_literals

from django.contrib.gis.db import models
from django.contrib.gis.geos import Point


class Shop(models.Model):
    name = models.CharField(max_length=100)
    location = models.PointField()
    address = models.CharField(max_length=100)
    city = models.PolygonField()

如果我打印{{loca.city}}，它将打印出GEOS对象，如下所示：

SRID=4326;POLYGON ((2.988282590688516 6............))

任何想法我如何绘制多边形，因为我正在绘制点？

更新II：

使用Shop.object.all（）打印出模型生成的内容

<QuerySet [<Shop: Shop object (1)>, <Shop: Shop object (2)>, <Shop: Shop object (3)>, <Shop: Shop object (4)>]>

数据库表看起来像存储多边形和点（x，y）

我考虑过手动使用查询（在视图中），但它不起作用（cursor.execute（“SELECT ST_AsText（city）FROM trial2_shop;）

使用此代码：

{% for each_model in loca %}

{{each_model.name}} <br>

{% endfor %}

输出是这样的：

HELLO 
PARIS 
France 
abc 

然后使用这个：

{% for each_model in loca %}

{{each_model.city}} <br>

{% endfor %}

输出是这样的：

SRID=4326;POLYGON ((2.988282590688516 6.287501448673132, -2.724608033516236 4.362344411133384, -5.624998658112493 4.800392361058798, -9.316404907598319 4.62520548641869, -7.29492053288002 -2.927082610924476, 8.701173214893267 -0.8189537900473602, 9.667970089758358 3.573231060257538, 5.537110715333732 4.362344411133384, 2.988282590688516 6.287501448673132)) 
SRID=4326;POLYGON ((2.379232127237539 48.99532183070828, 1.835408885125764 48.778601581576, 2.489095408472194 48.61544474629894, 2.780233103744227 48.87985458449839, 2.379232127237539 48.99532183070828)) 
SRID=4326;POLYGON ((4.921880363732911 48.86996904931716, 13.00781786260736 44.28238994198036, -8.08593213445636 32.47943349940858, -25.31249463205829 49.55890707900826, 5.364418038408538e-06 58.4058966101036, -8.789057134358529 49.10068218084409, 4.921880363732911 48.86996904931716)) 
SRID=4326;POLYGON ((10.10742321469805 59.8969527006269, 16.34765758882955 60.31310053764656, 15.02929821401315 57.87662999493084, 12.39257946438035 57.92333496310473, 10.10742321469805 59.8969527006269))

所以我确定存储的是多边形，但在检索时将其绘制在地图模板中是个问题...

Answer 1

您基本上需要在模板中使用leaflet polygon documentation。 你需要2件事来做这件事：

1. Polygon's coordinates列表： lst_coords = [[point.x, point.y] for point in shop_object.city] 这将产生列表/坐标对的列表。
2. 将坐标列表插入到传单多边形中： L.polygon(lst_coords, {color: 'red'}).addTo(map);

现在让我们将上面的内容应用到您的示例中：

1. 将property添加到模型中以返回坐标列表（仅为方便起见）：

   class Shop(models.Model):
       name = models.CharField(max_length=100)
       location = models.PointField()
       address = models.CharField(max_length=100)
       city = models.PolygonField()
   
       @property
       def city_coords_list(self):
            return [[point.x, point.y] for point in self.city]

2. 将以上内容集成到模板中：

   <script type="text/javascript">
   
     function map_init(map, options) {
       {% for each_model in loca %}
   
         L.polygon(
           {{ each_model.city_coords_list }}, {color: 'red'}
         ).bindPopup({{ each_model.name }}).addTo(map)
   
     {% endfor %}
     // Find a way to fit the map accordignly (search the docs)
     ;
   }