如何从Oracle DB获取xorm的表值？

Question

我尝试使用xorm并调用engine.Find（＆xxxx）方法获取值，但结果对象为空。我已经检查过它可以通过engine.Query（）方法得到结果。这意味着数据库连接正常工作。如何将结果放入usertest01？

package main

import (

    "database/sql"
    _ "github.com/mattn/go-oci8"
    "github.com/go-xorm/xorm"
)


type Usertest struct {
    Id       int64  `json:"id" xorm:"'id'"`
    Name     string `json:"name" xorm:"'name'"`
    Password string `json:"password"　xorm:"'password'"`
}

var engine *xorm.Engine

func main(){
    engine, err = xorm.NewEngine("oci8", getDSN())
    if err != nil {
        fmt.Println(err.Error())
    }

    var usertest01 []Usertest
    engine.Find(&usertest01)
    fmt.Println("--- result by struct. doesn't work ---")
    fmt.Println(usertest01)

    usertest02, err := engine.Query("select * from usertest")
    fmt.Println("--- result by Query. this works ---")
    fmt.Println(usertest02) 

}

安慰

[xorm] [info]  2019/04/13 18:24:45.986664 [SQL] SELECT "id", "name", "password" FROM "usertest"
--- result by struct. doesn't work---
[]
[xorm] [info]  2019/04/13 18:24:46.095214 [SQL] select * from usertest
--- result by Query. this works ---
[map[ID:[49] NAME:[78 65 77 69] PASS:[80 65 83 83]]]

Answer 1

我添加了返回实际表名的方法。

type Usertest struct {
    Id       int64  `json:"id" xorm:"'ID'"`
    Name     string `json:"name" xorm:"'NAME'"`
    Pass string `json:"pass" xorm:"'PASS'"`
}
// add this method
func (Usertest) TableName() string {
    return "USERTEST"
}

main(){
    ...
    ...
    engine.Find(&usertest01)
    fmt.Println(usertest01)
}