我有这个查询工作正常:
SELECT PLAY_ID, A0, WORD, CONTEXT
FROM playdata
WHERE A0 LIKE 'SOMETHING'
这产生了一些有用的输出。但是有一个名为PLAY_ID的列,它只是一个数字。有一个叫做戏剧的桌子,你可以在桌子上查找PLAY_ID,找出TITLE和YEAR。
所以我想输出三个东西,前两个来自查询表,CONTEXT和来自原始playdata的WORD:
TITLE | YEAR | WORD | CONTEXT
SELECT TITLE, CREATION_YEAR, A0, WORD, CONTEXT
FROM playdata
INNER JOIN plays
ON playdata.PLAY_ID=plays.PLAY_ID
WHERE A0 LIKE 'SOMETHING'