使用 Regex Powershell 获取第一个 = 之后的所有匹配项以及所有不带 = 的匹配项

Question

使用 Windows Powershell 正则表达式，我想在每一行中获取第一个 = 排除后的所有匹配项，即使还有其他 =。 但是，它还应该包含那些不以 = 开头的行，并且应该从行首到行尾。

我从中检索匹配项的代码示例：

ErrorMoving=You cannot=another.
ErrorTooMuchActions
=Too many changes=.{k}=12=aa
WorldErrorWait=An error has occurred.

我想要达到的结果：

You cannot=another.
ErrorTooMuchActions
Too many changes=.{k}=12=aa
An error has occurred.

我尝试做的事情：

(?<=\+?=).*

结果不正确：

You cannot=another.

Too many changes=.{k}=12=aa
An error has occurred.

Answer 1

也许

(?m)^.*?=

可以适合您的用例：

@'
ErrorMoving=You cannot=another.
ErrorTooMuchActions
=Too many changes=.{k}=12=aa
WorldErrorWait=An error has occurred.
'@ -replace '(?m)^.*?='

结果：

You cannot=another.
ErrorTooMuchActions
Too many changes=.{k}=12=aa
An error has occurred.

请参阅 https://regex101.com/r/2FfIou/1 了解正则表达式详细信息。