如何添加值到href中,其中一些值是来自AJAX和一些来自PHP循环。

问题描述 投票:0回答:1

上面这段代码显示的是所选病房的数据。

$("#sel_ward").change(function () {
    var wardid = $(this).val();

    $.ajax({
        url: 'getWard-details.php',
        type: 'post',
        data: {ward: wardid},
        dataType: 'json',

        success: function (response) {
            var len = response.length;
            // $("#sel_ward").empty();
            if (len == 0) {
                $("#sel_ward").append('<option value="">No Data Found</option>');
                var block_selected = response[i]['block_selected'];
                $("#blockid").val(block_selected);
            } else {
                for (var i = 0; i < len; i++) {
                    var id = response[i]['id'];
                    var name = response[i]['name'];

                    var ward_parshad_name = response[i]['ward_parshad_name'];
                    var ward_parshad_contact = response[i]['ward_parshad_contact'];
                    var ward_population = response[i]['ward_population'];
                    var ward_house_count = response[i]['ward_house_count'];
                    var ward_voters_count = response[i]['ward_voters_count'];
                    var ward_polling_both_count = response[i]['ward_polling_both_count'];

                    var block_selected = response[i]['block_selected'];
                    var zone_selected = response[i]['zone_selected'];
                    var sector_selected = response[i]['sector_selected'];
                    var block_area = response[i]['block_area'];
                    var block_region = response[i]['block_region'];

                    $("#ward-name-view").text(name);
                    $("#ward-parshad-name-view").text(ward_parshad_name);
                    $("#ward-parshad-contact-view").text(ward_parshad_contact);
                    $("#ward-population-view").text(ward_population);
                    $("#ward-house-view").text(ward_house_count);
                    $("#ward-voters-view").text(ward_voters_count);
                    $("#ward-polling-booth-view").text(ward_polling_both_count);
                }
            }
        }
    });
});

现在我有一个委员会的列表,其数据通过PHP获得。

<?php
// Fetch Committee
$sql_block = "SELECT * FROM committee";
$block_data = mysqli_query($con, $sql_block);

while ($row = mysqli_fetch_assoc($block_data)) {
    $committeeid = $row['sno'];
    $committee_name = $row['committee_name'];
    ?>
    <a id=committee href=""><span><?= $committee_name ?></span></a>
<?php } ?>

现在我想的是,只要有一个委员会被选中,我就想从选区的详细信息以及委员会的ID和名称中提取数据到下一页。这将提供更清晰的视图

javascript php ajax
1个回答
1
投票
<input type=hidden id=committee_id value=<?=$committeeid?>>
<input type=hidden id=committee_name value=<?=$committee_name?>>


    var committeeid = $("#committee_id").val();
 $("#committee").click(function(){
window.open("index.php?id="+committeeid+"", '_blank');
 });

我使用输入标签来存储值,并将其标记为隐藏。然后在点击委员会项目时,我从输入中获取数据,并相应地使用它。

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