我的下载Servlet运行两次

问题描述 投票:3回答:3

我有一个带下载servlet的gwt Web应用程序,我统计数据库中每个文件的下载量。当用户向服务器发送下载请求时,我的下载servlet运行两次,每次下载计数器计数2。但用户已发送请求的文件已下载一次。我不知道我的servlet对1个请求运行2次。

我下载的servlet:

public class DownloadServlet extends HttpServlet {

 private static final String UPLOAD_DIRECTORY = "c:\\update\\";
 private Connection con;

 @Override
 protected void doGet(HttpServletRequest req, HttpServletResponse resp)
         throws ServletException, IOException {

     Statement select=null;
     ResultSet result=null;

     try{

        Class.forName("com.mysql.jdbc.Driver");
        con = DriverManager.getConnection("jdbc:mysql://localhost:3306/laplasdb?useUnicode=true&characterEncoding=UTF-8","gwt","root");
        }catch(Exception ex){

        }
     String query = "SELECT * FROM TBL_Drive_Files WHERE id = '"+req.getParameter("fileid")+"'", filename="";
     InputStream filecontent=null;

     int filesize=0;
     try {
         select = con.createStatement();
         result = select.executeQuery(query);
         while (result.next()) {
             filename = result.getString(2);
             filesize = result.getInt(4);
             filecontent = result.getBinaryStream(5);
         }

         result.close();

     } catch(SQLException e) {
     }


     BufferedOutputStream output = null; 
     try { 

         resp.reset(); 
         resp.setContentType("application/octet-stream"); 
         resp.setContentLength(filesize); 
         resp.setHeader("Content-disposition", "attachment; filename=\"" + filename + "\""); 
         output = new BufferedOutputStream(resp.getOutputStream()); 
         for(int data; (data=filecontent.read()) != -1;) { 
             output.write(data); 
         } 
         output.flush(); 

         query = "Update TBL_Drive_Files SET count = count + 1 WHERE id = '"+req.getParameter("fileid")+"'";
         try {
            select = con.createStatement();
            select.execute(query);              

            select.close();
            con.close();
        } catch (SQLException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


     } 
     catch (IOException e) { 

         e.printStackTrace(); 
     } 
     finally {
     }
 }     

}

并且在客户端:

Button bd = new Button("Download", new ClickHandler(){
             public void onClick(ClickEvent event){
                final String link = GWT.getModuleBaseURL() + "download?fileid=3";

                RequestBuilder builder = new RequestBuilder(RequestBuilder.GET,link);

                try {
                     builder.sendRequest(null, new RequestCallback() {
                     public void onError(Request request, Throwable t) {
                        Window.alert("Error bei getExcel");
                    }
                    public void onResponseReceived(Request request,Response response){
                            int statuscode = response.getStatusCode();
                            if(statuscode == 200) {
                                    Window.Location.replace(link);
                      } else if(statuscode == 404) {
                        Window.alert("Service not available.");
                      }
                    }
                   });
                   } catch (RequestException re) {
                       Window.alert(re.toString());
                   }
             }
    });             
    RootPanel.get().add(bd);
java gwt servlets download
3个回答
2
投票

您提出两个请求。一位叫builder.sendRequest(null, new RequestCallback()另一个在状态为200 Window.Location.replace(link)]的回调中

顺便说一句,我希望这不是将要部署的代码。

  • 未处理的异常
  • 数据库操作应在自己的层中完成
  • 我看不到任何代码约定
  • 您应该只选择您真正需要的列
  • 不必要的声明
  • 还有许多其他要点,但是您首先应该解决此问题,然后您将能够自行发现错误并维护代码


0
投票

0
投票

我认为是第三方下载插件导致的,某些迅雷我认为这是由其他插件(如“ Thunder”)引起的]

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