Rest模板在异常处理程序后不返回响应实体

问题描述 投票:0回答:2

我有以下控制器方法

@PostMapping(consumes = "application/json",
             produces = "application/json")
public ResponseEntity<Board> createBoard(@Valid @RequestBody 
BoardRequestDTO boardRequestDTO) {
    Board board = new Board();
    board.setName(boardRequestDTO.getName());
    board.setCompanyId(Integer.valueOf(boardRequestDTO.getCompanyId()));
    board.setCode(boardRequestDTO.getCode());
    Board dbBoard = boardRepository.save(board);
    return new ResponseEntity<>(dbBoard, HttpStatus.CREATED);
} 

并为其处理验证错误提供以下异常处理程序

@ControllerAdvice
public class ExceptionHandlerConfig extends ResponseEntityExceptionHandler   {
    @Override
    protected ResponseEntity<Object>       
    handleMethodArgumentNotValid(MethodArgumentNotValidException ex, 
       HttpHeaders headers, HttpStatus status, WebRequest request) {
       ValidationErrorResponses validationErrorResponses = new 
       ValidationErrorResponses();
       for (FieldError fieldError : ex.getBindingResult().getFieldErrors())
       validationErrorResponses.addError(new ValidationError(fieldError.getField(),fieldError.getDefaultMessage()));

       ResponseEntity<Object> responseEntity = new ResponseEntity<Object> 
       (validationErrorResponses, HttpStatus.UNPROCESSABLE_ENTITY);
       return responseEntity;
    }

 }

当我通过Postman发送失败请求时,我得到了可预测的响应:

{
    "errors": [
         {
            "field": "companyId",
            "message": "Must be digit"
         }
    ]
}

但是当我尝试对这个端点实现以下单元测试时,我得到了org.springframework.web.client.HttpClientErrorException $ UnprocessableEntity:422 null

:

boardDTO.setCompanyId("");
HttpHeaders headers = new HttpHeaders();
headers.set("Content-Type", "application/json");
headers.set("Accept", "application/json");
HttpEntity<ValidationErrorResponses> httpEntity = new HttpEntity(boardDTO, headers);

ResponseEntity<ValidationErrorResponses> responseEntity = 
restTemplate.postForEntity(url, httpEntity, ValidationErrorResponses.class);

ValidationErrorResponses responseBody = responseEntity.getBody();
assertEquals(422, responseEntity.getStatusCode());
assertEquals("companyId", responseBody.getErrors().get(0).getField());
assertEquals("Must be digit", responseBody.getErrors().get(0).getMessage()); 

如果我的测试工作正常,我该怎么办?

java spring-boot exception resttemplate
2个回答
0
投票

当状态> = 400且<500时,restTemplate.postForEntity将抛出HttpClientErrorException。这里编写测试的简单方法是:

try {
  restTemplate.postForEntity(url, httpEntity, ValidationErrorResponses.class);
  fail("should throw exception");
} catch (HttpClientErrorException e) {
  // Asserts go here using `e`
}

0
投票

为了避免测试实现,我建议测试异常“已被抛出”。异常的返回消息应该是异常的单元测试的一部分:

@Test(expected = MethodArgumentNotValidException.class)
public void testMethodArgumentNotValidException() {
    boardDTO.setCompanyId("");
    HttpHeaders headers = new HttpHeaders();
    headers.set("Content-Type", "application/json");
    headers.set("Accept", "application/json");
    HttpEntity<ValidationErrorResponses> httpEntity = new HttpEntity(boardDTO, headers);

    ResponseEntity<ValidationErrorResponses> responseEntity = 
    restTemplate.postForEntity(url, httpEntity, ValidationErrorResponses.class);

}

否则问问自己是否可以通过用户验收测试来处理结果体?

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