(这是 Yitzhak Khabinsky 很好地回答了Manipulating tag names and output structure in SQL的后续)
我正在尝试以特定的 XML 格式从 Microsoft SQL Server 2016 中提取数据。我可以接近标准的 FOR XML 语句,但没有任何使用 XQuery 的经验——我怀疑这是一个优雅解决方案的核心。
-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, FirstName
VARCHAR(20), MiddleName VARCHAR(20), LastName VARCHAR(20));
INSERT @tbl (FirstName, MiddleName, LastName) VALUES
('Fred', 'A.','Smith'),
('Anna', NULL,'Polack');
-- DDL and sample data population, end
select * from @tbl
;WITH rs(x) AS
(
SELECT *
FROM @tbl
FOR XML PATH(''), TYPE, ROOT('root')
)
SELECT
x.query('for $x in /root/*
return <Answer name="{local-name($x)}">
<value>{data($x)}</value>
</Answer>') AS Result
FROM rs
产生以下内容:
<Answer name="ID">
<value>1</value>
</Answer>
<Answer name="FirstName">
<value>Fred</value>
</Answer>
<Answer name="MiddleName">
<value>A.</value>
</Answer>
<Answer name="LastName">
<value>Smith</value>
</Answer>
<Answer name="ID">
<value>2</value>
</Answer>
<Answer name="FirstName">
<value>Anna</value>
</Answer>
<Answer name="LastName">
<value>Polack</value>
</Answer>
我想获得更明确的输出枚举,如下所示:
<Answer name="ID_1">
<value>1</value>
</Answer>
<Answer name="FirstName_1">
<value>Fred</value>
</Answer>
<Answer name="MiddleName_1">
<value>A.</value>
</Answer>
<Answer name="LastName_1">
<value>Smith</value>
</Answer>
<Answer name="ID_2">
<value>2</value>
</Answer>
<Answer name="FirstName_2">
<value>Anna</value>
</Answer>
<Answer name="LastName_2">
<value>Polack</value>
</Answer>
我可以通过使用来破解它:
select STRING_AGG('<Answer name="'+ColKey+'">'+
'<value>'+ColValue+'</value></Answer>',' ')
from
(
select tab.* from @tbl
CROSS APPLY (
VALUES ('FirstName_'+cast(ID as varchar), FirstName),
('LastName_'+cast(ID as varchar), LastName)
) tab(ColKey, ColValue)
)t
但我确信有一种使用 XQuery 的更优雅的方式
不需要 string_agg()
例子
Select [Answer/@name] = concat('ID','_',id)
,[Answer/value] = id
,null
,[Answer/@name] = concat('FirstName','_',id)
,[Answer/value] = FirstName
,null
,[Answer/@name] = concat('MiddleName','_',id)
,[Answer/value] = MiddleName
,null
,[Answer/@name] = concat('LastName','_',id)
,[Answer/value] = LastName
From @tbl
For xml path('')
结果
<Answer name="ID_1">
<value>1</value>
</Answer>
<Answer name="FirstName_1">
<value>Fred</value>
</Answer>
<Answer name="MiddleName_1">
<value>A.</value>
</Answer>
<Answer name="LastName_1">
<value>Smith</value>
</Answer>
<Answer name="ID_2">
<value>2</value>
</Answer>
<Answer name="FirstName_2">
<value>Anna</value>
</Answer>
<Answer name="MiddleName_2" />
<Answer name="LastName_2">
<value>Polack</value>
</Answer>