Swift - 解析JSON并检索数据

问题描述 投票:2回答:1

我在Xcode上使用Swift,我尝试解析JSON文件以检索有关附近商店的一些数据。我的源代码如下:

import GooglePlaces

import SwiftyJSON

class Place {
    let name: String
    let coordinates: CLLocationCoordinate2D

    init(diction:[String : Any])
    {
        let json = JSON(diction)
        name = json["name"].stringValue //as! String

        let lat = json["geometry"]["location"]["lat"].doubleValue as CLLocationDegrees
        let long = json["geometry"]["location"]["lng"].doubleValue as CLLocationDegrees
        coordinates = CLLocationCoordinate2DMake(lat, long)
    }
}

class ViewController: UIViewController, MKMapViewDelegate, SceneLocationViewDelegate {


var urlString = "https://maps.googleapis.com/maps/api/place/nearbysearch/json?"
        urlString += "&location=51.507514,-0.073603"
        urlString += "&radius=1500" //meters
        urlString += "&name=Specsavers"
        urlString += "&key=**************************" 

        guard let url = URL(string: urlString) else {return}
        var places = [Place]()

        var request = URLRequest(url:url)
        request.httpMethod = "GET"

        let task = URLSession.shared.dataTask(with: request as URLRequest) {
            data, response, error in
            print("HEREurlSession")
            if let content = data {
                do {
                    let json = try JSONSerialization.jsonObject(with: content, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
                    print(json) // json results are printed fine here
                    if let results = json["results"] as? [[String : Any]] {
                        for place in results {
                            places.append(Place(diction: place))
                        }

                    }
                    else {
                        print("return")
                    }

                }
                catch{

                }
            }
        }
        task.resume()

        let size = places.count
        print("HERE: ", size)

}

构建成功,但输出是size = 0,这意味着我不检索数据,变量places为空。我不知道它是否完全相关,但我得到以下警告:Cast from 'MDLMaterialProperty?!' to unrelated type '[[String : Any]]' always fails为我的源代码中的if let results = json["results"] as? [[String : Any]]行。

为什么我没有正确解析JSON文件而我没有检索到我想要的数据?

json swift google-places-api
1个回答
2
投票

URLSession.shared.dataTask(with:)是异步的。这意味着,它在后台运行。你正在执行

let size = places.count
print("HERE: ", size)

dataTask仍在工作。

相反,您应该在完成处理程序中使用您的结果:

    let task = URLSession.shared.dataTask(with: request as URLRequest) {
        data, response, error in
        print("HEREurlSession")
        if let content = data {
            do {
                let json = try JSONSerialization.jsonObject(with: content, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
                                    print(json)
                if let results = json["results"] as? [[String : Any]] {
                    for place in results {
                        places.append(Place(diction: place))
                    }

                }
                else {
                    print("return")
                }

            }
            catch{

            }
        }

        // Use your result here
        let size = places.count
        useResultSize(size)

    }
    task.resume()

    func useResultSize(_ size: Int) {
        // Use your result here
        print("HERE: ", size)
    }

UPDATE

看来,你错过了异步执行实际意味着什么。让我试着解释一下。

让我们在代码中标记执行顺序:

enter image description here

首先,执行代码的红色部分。程序执行从顶部开始,然后移到底部的红色框,并且仅在此之后(一旦网络请求完成),执行绿色部分。

这意味着,您只能在代码的绿色部分中使用网络请求的结果。在绿色部分之外,不保证结果可用。

如果你遵循我的初步建议,那么一切都应该有效。请在我的操场上看到成功执行:

enter image description here

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