我是android新手,我正在尝试构建一个android应用程序,我使用单例模式来显示警报对话框,但是当我运行应用程序时它崩溃了。 我尝试删除单例,它工作正常。 这是我的代码 LoadingDialog.java
public class LoadingDialog {
private Activity activity;
private AlertDialog dialog;
private static LoadingDialog loadDialog;
public LoadingDialog(Activity activity) {
this.activity = activity;
}
public static synchronized LoadingDialog getInstance(Activity activity) {
if (loadDialog == null) {
loadDialog = new LoadingDialog(activity);
}
return loadDialog;
}
public void startDialog() {
AlertDialog.Builder builder = new AlertDialog.Builder(activity);
LayoutInflater inflater = activity.getLayoutInflater();
builder.setView(inflater.inflate(R.layout.loading,null));
builder.setCancelable(false);
dialog = builder.create();
dialog.show();
}
public void closeDialog() {
dialog. Dismiss();
}
}
MainActivity.java
private ActivityMainBinding binding;
private LoadingDialog dialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
binding = ActivityMainBinding.inflate(getLayoutInflater());
setContentView(binding.getRoot());
dialog = LoadingDialog.getInstance(MainActivity.this);
binding.btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
dialog.startDialog();
}
});
它给了我这个错误
FATAL EXCEPTION: main
Process: com.mkandeel.gmarek, PID: 20063
android.view.WindowManager$BadTokenException: Unable to add window -- token android.os.BinderProxy@4723521 is not valid; is your activity running?
at android.view.ViewRootImpl.setView(ViewRootImpl.java:678)
at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:342)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:93)
at android.app.Dialog.show(Dialog.java:316)
at com.mkandeel.gmarek.LoadingDialog.startDialog(LoadingDialog.java:30)
at com.mkandeel.gmarek.MainActivity$1.onClick(MainActivity.java:52)
at android.view.View.performClick(View.java:5610)
at com.google.android.material.button.MaterialButton.performClick(MaterialButton.java:1211)
at android.view.View$PerformClick.run(View.java:22265)
at android.os.Handler.handleCallback(Handler.java:751)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:154)
at android.app.ActivityThread.main(ActivityThread.java:6077)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:866)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:756)
那么我的代码有什么问题呢? 预先感谢。
我尝试通过公开我的收缩器来使用没有单例的类,并且它可以正常工作
我认为错误是当你调用 startDialog() 时你的 Activity 为空:
binding = ActivityMainBinding.inflate(getLayoutInflater());
setContentView(binding.getRoot());
dialog = LoadingDialog.getInstance(MainActivity.this);
binding.btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
dialog.startDialog();
}
});
因为当您调用 getInstance 时,您通过 param 使用 Activity 创建了实例,但 LoadingDialog 范围内的 Activity 尚未初始化,因此为 null。然后,当你调用startDialog()时,Builder中的activity为null:
AlertDialog.Builder builder = new AlertDialog.Builder(activity);
因此,解决方案可能是:
public static synchronized LoadingDialog getInstance(Activity activity) {
if (loadDialog == null && this.activity == activity) {
this.activity = activity;
loadDialog = new LoadingDialog(activity);
}
return loadDialog;
}
我也在检查活动实例,因为如果您从另一个活动调用单例类,则可能会导致内存泄漏。
无论如何,IMO 不需要单例类来显示对话框,也不需要
synchronized
关键字
当您显示不再存在的上下文/活动的对话框时,会发生此错误。
在调用 .show() 之前检查活动/上下文是否未完成
public void startDialog() {
AlertDialog.Builder builder = new AlertDialog.Builder(activity);
LayoutInflater inflater = activity.getLayoutInflater();
builder.setView(inflater.inflate(R.layout.loading,null));
builder.setCancelable(false);
dialog = builder.create();
if (!activity.isFinishing()){
dialog.show();
}
}