分段故障内存转储

Question

我有以下代码。当我将数组'ADDRESS.Person'写入任何值时，我收到了“分段故障内存转储”的错误。任何人请帮我解决问题。

#include <stdio.h>

typedef struct
{
    char Person[15];
} stName;

typedef struct
{
    stName      Name;
} stSociety;

stSociety* SOCIETY;

#define ADDRESS    SOCIETY->Name


int main()
{

    int i;

    for (i=0; i<32; i++)
    {
        ADDRESS.Person[i] = 0;
    }

    printf("ADDRESS.Person=%s\n", ADDRESS.Person);

    printf("Finished");
    return 0;
}

Answer 1

你刚刚声明了结构，你也需要创建它们，因此，SOCIETY指向什么都没有。你也在迭代32个值，而char数组中只有15个。我修改了代码，希望你会得到这里有个主意

#include <stdio.h>

typedef struct
{
    char Person[15];
} stName;

typedef struct
{
    stName      Name;
} stSociety;

#define ADDRESS    SOCIETY->Name


int main()
{

stSociety* SOCIETY,sample;
SOCIETY = &sample;


    int i;

    for (i=0; i<15; i++)
    {
       ADDRESS.Person[i] = '0';

    }

    printf("ADDRESS.Person=%s\n", ADDRESS.Person);

    printf("Finished");
    return 0;
}