如何实现JPQL查询?

问题描述 投票:-2回答:1

我在PostgreSQL中有有效的查询:

select s.id, s.seat_number as available_seat, s.row_number as available_row, rm.room_name as screening_room
from seats s
         join rooms rm on rm.id=s.room_id
         left join (
    select r.seat_id from reserved_seats r
                              join reservations  res on res.id=r.reservation_id AND res.screening_id = 3 ) res on res.seat_id=s.id
where res.seat_id is null AND s.room_id=3
ORDER BY s.id;

但是将其翻译为JPA查询语言时会出错。

enter image description here

我可以在JPQL中使用嵌套的SELECT吗?

答案是使用本机查询

@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)
java sql jpa jpql
1个回答
0
投票

答案是使用本机查询

@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)
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