流明/ Laravel问题中存在多个查询的问题

Question

我只想在这种特定情况下寻求帮助。因此，在我的应用程序中，我们希望有一个全局搜索功能，在其中放置1个字符串，然后必须使用laravel雄辩地在db中多次搜索该字符串，但是由于我在多个where位置有一个字符串，然后我有withcount（我将在以后显示）。有人可以帮我解决这个问题吗？不胜感激

这里是代码

    $result = [];
    $sort_order = "DESC";
    $post_param = $request->json()->all();
    $filters = $post_param['filters'];

    if($post_param['sortOrder'] > 0)
    {
        $sort_order = "ASC";
    }

    $financing_applications   = $this->financing_application->model();

    $data                     = $financing_applications::with('financing_application_data.business_type','financing_product_approval.financing_product')->withCount('financing_application_attachments as attachment');

    foreach($filters as $key => $filter){
        $value = $filter['value'];
        if($value != ""){
            switch($key){
                case "start_date_range":
                    $data   = $data->where('submission_date','>=',$value);
                    break;

                case "end_date_range":
                    $data   = $data->where('submission_date','<=',$value);
                    break;

                case "status":
                    $data   = $data->where($key,"LIKE","%$value%");
                    break;

                case "attachment_count":
                    $data   = $data->having('attachment_count','=',$value);
                    break;

                case "company_name":
                case "telephone":
                case "city":
                    if($key == "telephone"){
                        $key = "personal_phone_no";
                    }
                    if($key == "city"){
                        $key = "company_city";
                    }
                    $data   = $data->whereHas('financing_application_data',function($query) use ($key,$value) {
                        $query->where($key,"LIKE","%$value%");
                    });
                    break;

                case "business_type":
                    $data->whereHas('financing_application_data.business_type',function($query) use ($key,$value){
                        $query->where('business_type_parent','LIKE',"%$value%");
                    });
                    break;

                case "loan_type":
                case "loan_partner":
                    $data->whereHas('financing_product_approval.financing_product',function($query) use ($key,$value){
                        $query->where($key,"LIKE","%$value%");
                    });
                    break;

                case "global": //This is the problem
                    $data   = $data->whereHas('financing_application_data.business_type',function($query) use ($key,$value){
                        $query->whereRaw("business_type_parent LIKE ? ",["%$value%"]);
                    });
                    $data   = $data->whereHas('financing_product_approval.financing_product',function($query) use ($key,$value){
                        $query->whereRaw("loan_type LIKE ? OR loan_partner LIKE ?",["%$value%","%$value%"]);
                    });
                    break;
            }
        }
    }

    $total_records  = $data->count();
    $result         = $data->orderBy($post_param['sortField'],$sort_order)->skip($post_param['first'])->take($post_param['rows'])->get();

    return [
        "financing_applications" => $result,
        "total_records" => $total_records,
        "message" => "",
        "status" => 200,
    ];

因此，在这种情况下，我的预期结果只是能够使用所有情况，并将其组合到switch语句中的“ global”情况下。

有没有人遇到相同的问题并且有解决方案？上面的全局函数不起作用，因为在何处和何处有何期望为AND而不是OR ...并且我一直在寻找解决方案，但它太复杂了，我不知道此问题的确切关键字

这里是您需要的一些信息

"laravel/lumen-framework": "5.3.*"

更新：抱歉，如果您中的某些人误解了我的问题，那么问题仅在于大小写“ global”，而其他情况则在于“ whereHas”语法以过滤关系。关于case全局应该能够组合“ Where”和“ WhereHas”的情况，我已经这样做了，但是由于没有“ orWhereHas”（据我所知），因此它将返回空，因为它被识别为“ AND”语句

这里我给你JSON负载：

{
"filters": {
    "global": {
        "matchMode": "undefined",
        "type": "string",
        "value": "Man"
    },
    "start_date_range": {
        "matchMode": "undefined",
        "type": "date",
        "value": ""
    },
    "end_date_range": {
        "matchMode": "undefined",
        "type": "date",
        "value": ""
    },
    "company_name": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "business_type": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "telephone": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "city": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "attachment_count": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "loan_type": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "loan_partner": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    },
    "status": {
        "matchMode": "undefined",
        "type": "string",
        "value": ""
    }
},
"first": 0,
"rows": 8,
"sortOrder": -1,
"sortField": "submission_date"
}

所以目标是使filter ['global'] ['value']返回某些东西，这就是所有问题，希望它能澄清一些理解的问题

Answer 1

我找到了解决此问题的方法，我必须用has替换whereHas语法，该语法可以具有在这种情况下所需的OR逻辑。

谢谢