如何在 laravel 预加载中添加别名以选择查询

Question

我想优化我的代码，所以我试图只选择我实际需要的那些字段进入

questionBankOptions

部分但问题是我收到

Integrity constraint violation: 1052 Column 'id' in field list is ambiguous

的错误所以试图删除这部分

select('id as optionId','question_bank_id','option','option_image','correct','status')

它在那里在

questionBankOptions

中，我没有看到任何错误。所以我不明白为什么我会收到这个错误。

$assesmentQuestion = AssesmentQuestion::with(['questionBank:id,remarks,question,question_img,question_format','questionCategories','questionBankOptions' =>  function($q){
                $q->select('id as optionId','question_bank_id','option','option_image','correct','status')->where('status',0);
            }])->select(['id','question_bank_id','preferences','assesment_id'])->where('assesment_id',$id)->orderBy('preferences','ASC')->get();

完整错误

Integrity constraint violation: 1052 Column 'id' in field list is ambiguous (SQL: select `id` as `optionId`, `question_bank_id`, `option`, `option_image`, `correct`, `status`, `question_banks`.`id` as `laravel_through_key` from `question_bank_options` inner join `question_banks` on `question_banks`.`id` = `question_bank_options`.`question_bank_id` where `question_banks`.`id` in (61, 62, 65, 66, 67, 68, 70, 71, 72, 73, 75) and `status` = 0)

Answer 1

查询不知道

'id as optionId'

应该在哪个 id 上，因为

questionBank

显然使用了内部连接。您需要指定表名。我猜你想要

question_bank_options

的 id，所以只需像下面这样添加它。

$q->select('question_bank_options.id as optionId','question_bank_id',...