在ios7中解析NSXMLElement

问题描述 投票:0回答:1

我有

 "<message xmlns=\"jabber:client\" type=\"chat\" to=\"[email protected]\" from=\"[email protected]/44b97a48-f761-4332-a7a6-734e8e3d81f2\" id=\"168AA10F-B3B1-430B-9EDF-2A6126161CF5\" timestamp=\"2014-03-29 01:23:16 +0000\"><body>Yt itygvgy glkbhlkblkblkblblibibilub</body><request xmlns=\"urn:xmpp:receipts\"></request></message>"

我需要获取'to'属性的值。我用

         NSArray * children =  [queryElements children];
            NSArray *  attributes = [queryElements attributes];
            NSXMLElement *qq = children[1];

            NSXMLElement *resultElements = [qq elementForName: @"to" xmlns: @"jabber:client"];

            NSLog(@"TWST :\n%@", resultElements);

然后获取(空)。

我通过]得到这个>

                NSArray * children =  [queryElements children];
           NSLog(@"children:\n%@ :\n", children);
            NSXMLElement *qq = children[1];
            NSArray * children2 =  [qq children];
            NSLog(@"22:\n%@ :\n", children2[0]); //body
            NSArray * children333 =  [qq attributes];
            NSLog(@"3333:\n%@ :\n", children333[2]); //from

还有更聪明的方法吗?

我有“

xml web-services nsxmlparser nsxml nsxmlelement
1个回答
0
投票

如果要从数组中获取所有属性,则可以使用这种方式:

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