mysql搜索数字范围的逗号列表

Question

在我的一个表字段中，我包含年龄范围。它们的格式如下

27-51,18-28,10-17
37-55,60-70
1-5,11-16,30-32,60-90
etc

我正在尝试构建一个SELECT语句，我可以搜索我的给定年龄是否属于任何范围......例如

SELECT * from table where age IN (1-5,11-16,30-32,60-90)

但是它会在给定范围内搜索

如果我只使用类似的东西，我可以做到这一点......

WHERE age 
BETWEEN
SUBSTRING_INDEX(personsAge,"-",1) + 0 AND
SUBSTRING_INDEX(personsAge,"-",-1) + 0

但是如果我有多个范围怎么能完成这个呢？

Answer 1

这是一个扩展我的评论的答案。我假设你可以创建一个函数：

注意：这是为了Sql Anywhere。请调整MySql的语法（尤其是切换参数的locate函数）。代码没有生产就绪，我遗漏了一些有效性检查。我假设列中的值都格式正确。

注意2：这是有人向您转储可怕的数据库设计并要求您解决问题的情况之一。请避免创建对此类解决方案的需求。

功能：

CREATE FUNCTION "DBA"."is_in_range"(age_range varchar(255), age int)
returns int
begin 
  declare pos int;
  declare pos2 int;
  declare strPart varchar(50);
  declare strFrom varchar(10);
  declare strTo varchar(10);
  declare iFrom int;
  declare iTo int;

  while 1 = 1 loop
    set pos = locate(age_range, ',');
    if pos = 0 then
      -- no comma found in the rest of the column value -> just take the whole string
      set strPart = age_range;
    else 
      -- take part of the sting until next comma
      set strPart = substr(age_range, 1, pos - 1);
    end if;
    -- we are parsing the min-max part and do some casting to compare with an int
    set pos2 = locate(strPart, '-');
    set strFrom = substr(strPart, 1, pos2 - 1);
    set strTo = substr(strPart, pos2 + 1);
    set iFrom = cast(strFrom as int);
    set iTo = cast(strTo as int);

    if age between iFrom and iTo then
      return 1;
    end if;
    -- if at end of age_range then quit
    if pos = 0 then
      return 0;
    end if;
    -- get the next part of the string after the comma
    set age_range = substr(age_range, pos + 1);
    set pos = locate(age_range, ',', pos);
  end loop;

  return 0;
end;

测试数据：

create local temporary table #tmpRanges (ident int, age_range varchar(255));
insert into #tmpRanges (ident, age_range) values (1, '27-51,18-28,10-17');
insert into #tmpRanges (ident, age_range) values (2, '37-55,60-70');
insert into #tmpRanges (ident, age_range) values (3, '1-5,11-16,30-32,60-90');
insert into #tmpRanges (ident, age_range) values (4, '1-50');

呼叫：

select * from #tmpRanges where is_in_range(age_range, 51) = 1;
select * from #tmpRanges where is_in_range(age_range, 10) = 1;
select * from #tmpRanges where is_in_range(age_range, 9) = 1;
etc...