如何在UIPickerView中更改所选行的颜色

问题描述 投票：19回答：10

好吧，也许我错过了一些非常简单的事情，如果是这样的话我会道歉，但是，我已经搜索了标题的每一个排列并且没有找到！所以这就是我想要做的事情：当选择该行时，将我正在使用的标签的背景颜色更改为2组件选择器视图中的行视图。所以我认为这会奏效：

if (row == [pickerview selectedRowForComponent])
    viewlabel.backgroundColor = redcolor;

但这不起作用。它似乎随意选择要着色的行，有时甚至会给出错误的访问错误。我试过所有不同的条款都没有效果！任何建议将不胜感激！！

这是完整的方法：

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{

    if (component == kNumberComponent) {


#define PICKER_LABEL_FONT_SIZE 24
#define PICKER_LABEL_ALPHA 1.0
        // UIFont *font = [UIFont boldSystemFontOfSize:PICKER_LABEL_FONT_SIZE];
        UIFont *font = [ UIFont fontWithName:@"AppleGothic"  size:24];
        UILabel *carsLabel =[ [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 75, 50) ]autorelease];
        //[picker selectRow:row inComponent:component animated:YES];
        NSString *pickerText = [self.numbers objectAtIndex:(int)row];
        carsLabel.text = pickerText;
        carsLabel.textAlignment = UITextAlignmentCenter;
        NSLog(@"carsLabel = %@",carsLabel.text);
        //carsLabel.text = @"maybe because the string isn't long enough";
        carsLabel.textColor = [UIColor blackColor];
        carsLabel.font = font;





        carsLabel.opaque = YES;


        [view addSubview:carsLabel];

        return carsLabel;   
    } else {
        UIFont *font = [ UIFont fontWithName:@"AppleGothic"  size:18];

        UILabel *carsLabel = [[[UILabel alloc] initWithFrame:CGRectMake(0, 0, 225, 50)] autorelease];
        id fact = [self.facts objectAtIndex:(int)row];
        NSString *pickerText = @"Dictionary Entry";
        if ( [fact isKindOfClass:[NSString class]]) {


            pickerText = [self.facts objectAtIndex:(int)row];

        } 
        carsLabel.text = pickerText;
        carsLabel.textAlignment = UITextAlignmentCenter;
        NSLog(@"carsLabel = %@",carsLabel.text);
        //carsLabel.text = @"maybe because the string isn't long enough";
        carsLabel.textColor = [UIColor blackColor];
        carsLabel.font = font;
        if ( row == 0) {
        carsLabel.backgroundColor = [UIColor redColor];

        }
        //carsLabel.backgroundColor = [UIColor colorWithPatternImage:[UIImage imageNamed:@"blackboard.png"]];;
        carsLabel.opaque = YES;

        [view addSubview:carsLabel];

        return carsLabel;
    }


    return nil;
}
iphone uipickerview
10个回答
11
投票

通常，我使用这种方法：

我使用自定义视图来显示行项目

-(UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{

    UILabel *label = (id)view;

    if (!label)
    {

        label= [[UILabel alloc] initWithFrame:CGRectMake(0.0f, 0.0f, [pickerView rowSizeForComponent:component].width, [pickerView rowSizeForComponent:component].height)];
        label.textAlignment = NSTextAlignmentCenter;
        label.textColor = [UIColor whiteColor];
        label.text = _arrayStringPicker[row];

    }  

    return label;

我改变选择的行的颜色：

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{

    UILabel *labelSelected = (UILabel*)[pickerView viewForRow:row forComponent:component];
    [labelSelected setTextColor:[UIColor redColor]];

}
0
投票

Swift版本的@ alessandro-pirovano回答

func pickerView(_ pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusing view: UIView?) -> UIView {

    let rowSize = pickerView.rowSize(forComponent: component)
    let width = rowSize.width
    let height = rowSize.height
    let frame = CGRect(x: 0, y: 0, width: width, height: height)
    let label = UILabel(frame: frame)
    label.textAlignment = .center
    label.text = rows[row]

    return label
}

func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

    guard let label = pickerView.view(forRow: row, forComponent: component) as? UILabel else {
        return
    }
    label.backgroundColor = .orange
}
6
投票

viewForPicker的正确格式是：

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{
    UILabel *label = (UILabel*) view;
    if (label == nil)
    {
        label = [[UILabel alloc] init];
    }

    [label setText:@"Whatever"];

    // This part just colorizes everything, since you asked about that.

    [label setTextColor:[UIColor whiteColor]];
    [label setBackgroundColor:[UIColor blackColor]];
    CGSize rowSize = [pickerView rowSizeForComponent:component];
    CGRect labelRect = CGRectMake (0, 0, rowSize.width, rowSize.height);
    [label setFrame:labelRect];

    return label;
}

上面代码的问题是：它使标签着色，而不是选择器本身。因此，当您滚动到一端或另一端时，会有一个空白点，您可以看到白色背景。设置[myPicker setBackgroundColor ...]并不能达到人们所希望的效果。

4
投票

//我们想要的帧的CGRectMake值

UIPickerView *myPickerView = [[UIPickerView alloc] initWithFrame:CGRectMake(0,0, self.view.bounds.size.width, self.view.bounds.size.height)];

// add the UIPickerView to your viewcontroller [mainView addSubview:myPickerView];

// set the selectionindicator to none myPickerView.showsSelectionIndicator = NO;

//定义我们想要使用的图像

UIImage *selectorImage = [UIImage imageNamed:@"selectionIndicator.png"];

UIView *customSelector = [[UIImageView alloc] initWithImage:selectorImage];

//将x和y值设置为UIPickerView上要放置图像的位置

//将宽度和高度值设置为图像的宽度和高度

customSelector.frame = CGRectMake(10,(myPickerView.bounds.size.height / 2) + 16, self.view.bounds.size.width – 10, 47);

//也将自定义selectionIndicator添加到同一个viewcontroller

[mainView addSubview:customSelector];
4
投票

解决了！声明2个实例变量：selectedView和oldView。然后以下代码可以解决问题：

if (self.oldView != nil)
        self.oldView.backgroundColor = [UIColor clearColor];

self.selectedView = [picker viewForRow:row forComponent:kNumberComponent];
        self.selectedView.backgroundColor = [UIColor redColor];
        [self.selectedView setNeedsDisplay];
        self.oldView = self.selectedView;
4
投票

快速实施

extension PickerViewController: UIPickerViewDelegate {
    func pickerView(pickerView: UIPickerView, attributedTitleForRow row: Int, forComponent component: Int) -> NSAttributedString? {
        var color: UIColor!
        if pickerView.selectedRowInComponent(component) == row {
            color = UIColor.redColor()
        } else {
            color = UIColor.blackColor()
        }

        let attributes: [String: AnyObject] = [
            NSForegroundColorAttributeName: color,
            NSFontAttributeName: UIFont.systemFontOfSize(15)
        ]

        return NSAttributedString(string: rows[row], attributes: attributes)
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        //this will trigger attributedTitleForRow-method to be called
        pickerView.reloadAllComponents()
    }
}
2
投票

调用UIPickerView实例的-viewForRow:forComponent:方法来获取UIView *对象。然后设置该视图的背景UIColor。

0
投票

目前还不清楚您将上述代码放在何处。是在-pickerView:viewForRow:forComponent:reusingView:？这应该是它应该的地方。您确定要维护指向该特定视图的标签的指针吗？你崩溃的事实暗示你可能不是。更大的代码块，包括您放置它的位置，将会很有帮助。

0
投票

这对我有用：

  1. 将UIView添加为UIPickerView的子视图
  2. 将它限制为使用UIPickerView输入的Y并且具有相同的宽度
  3. 给它的高度等于pickerView(_ pickerView: UIPickerView, rowHeightForComponent component: Int) -> CGFloat返回的高度
  4. 使其半透明并按照您想要的方式着色

*其他解决方案（对于行的行或属性字符串的自定义视图）在快速滚动时是错误的。

0
投票

UIPickerView有委托为行和组件设置NSAttributeString我们可以设置属性颜色，如下所示：

- (NSAttributedString *)pickerView:(UIPickerView *)pickerView attributedTitleForRow:(NSInteger)row forComponent:(NSInteger)component {
    NSDictionary *attrs = @{NSForegroundColorAttributeName : [UIColor redColor]};
    NSString *title = @"title"
    return [[NSAttributedString alloc] initWithString:title attributes:attrs];

}

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