推送数组中的值以匹配特定格式

Question

我有一个api给我价值，我试图推进我的阵列。我的数组结构如下

this.rolesArr = [
  { label: 'Admin', value: '1' },
  { label: 'Manager', value: '2' },
  { label: 'Recruiter', value: '3' },
  { label: 'Operational', value: '4' }
];

我收到的数据是这样的

{1: "System Admin", 2: "Internal Account Manager", 3: "CAT Manager", 4: "HR Admin", 5: "HR Manager", 6: "HR Recruiter", 7: "Candidate", 8: "Operations administrator"}

如何将其推送到阵列以匹配结构？

我正在尝试这个但是被卡住了

for(let i = 0; i < roles.roles.length; i++) {
  this.rolesArr.push([ { label: , value: '1' }])
}

Answer 1

您可以使用Object.entries将键值对作为数组获取，然后使用Array#map方法生成数组。

let data = {1: "System Admin", 2: "Internal Account Manager", 3: "CAT Manager", 4: "HR Admin", 5: "HR Manager", 6: "HR Recruiter", 7: "Candidate", 8: "Operations administrator"};

let res = Object.entries(data).map(([value, label])=>({ label, value }))

console.log(res)

要将这些值添加到现有数组中，请使用Spread syntax和Array#push方法。

this.rolesArr.push(...res)

Answer 2

您可以使用函数Object.entries获取标签和值，然后使用函数reduce构建所需的输出。

let obj = {  1: "System Admin",  2: "Internal Account Manager",  3: "CAT Manager",  4: "HR Admin",  5: "HR Manager",  6: "HR Recruiter",  7: "Candidate",  8: "Operations administrator"},
    result = Object.entries(obj).reduce((a, [label, value]) => a.concat({label, value}), []);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

只需通过更正您提供的代码来解决您的问题，以便您可以确定您做错了什么。

var data = { 1: "System Admin", 2: "Internal Account Manager", 3: "CAT Manager", 4: "HR Admin", 5: "HR Manager", 6: "HR Recruiter", 7: "Candidate", 8: "Operations administrator" };
    var entries = Object.entries(data);
    var rolesArr = [];
    for (var i = 0; i < entries.length; i++) {
        this.rolesArr.push({ label: entries[0][1], value: entries[0][0] })
    }
    console.log(this.rolesArr);