我在几个页面中一直使用django内置分页(is_paginated)。他们都很好。除搜索页面外,仅应基于过滤的查询集显示分页。
我已经检查了其他几个线程,但是没有太大帮助。
How do I use pagination with Django class based generic ListViews?
这里是我到目前为止的迷你版:-
1] views.py
class SearchBookView(ListView):
template_name = 'books/search_book.html'
paginate_by = '2'
context_object_name = 'book'
form_class = SearchBookForm
def get(self, request):
form = self.form_class(request.GET or None)
if form.is_valid():
filtered_books = self.get_queryset(form)
context = {
'form' : form,
'book' : filtered_books,
}
else:
context = {'form': form}
return render(request, self.template_name, context)
def get_queryset(self, form):
filtered_books = Book.objects.all()
if form.cleaned_data['title'] != "":
filtered_books = filtered_books.filter(
title__icontains=form.cleaned_data['title'])
return filtered_books
def get_context_data(self):
context = super(SearchBookView, self).get_context_data()
return context
2)search_book.html(模板)
{% crispy form %}
{% if book %}
<p>Found {{ book|length }} book{{ book|pluralize }}.</p>
{% for book in book %}
<div class="card">
<div style="height:170px; border:solid #111111;" class="col-md-3">
Ima
</div>
<div class="whole-card col-md-9">
<div class="title">"{{ book.title }}"</div>
<div>{{ book.description }}</div>
<a href="{% url 'book:detail' book.id %}" class="btn">Read More</a>
</div>
</div>
{% endfor %}
{% else %}
<p>No book matched your searching criteria.</p>
{% endif %}
{% if is_paginated %}
<div class="pagination">
<span class="page-links">
{% if page_obj.has_previous %}
<a href="?page={{ page_obj.previous_page_number }}">previous</a>
{% endif %}
<span class="page-current">
Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }}.
</span>
{% if page_obj.has_next %}
<a href="?page={{ page_obj.next_page_number }}">next</a>
{% endif %}
</span>
</div>
{% endif %}
forms.py
class SearchBookForm(forms.Form):
title = forms.CharField(max_length=20)
def __init__(self, *args, **kwargs):
self.helper = FormHelper()
self.helper.add_input(Submit('search', 'Search', css_class='btn'))
self.helper.form_method = 'GET'
self.helper.layout = Layout('title')
super(SearchBookForm, self).__init__(*args, **kwargs)
------------------ UPDATE ------------------
尽管我理解Daniel Roseman的回答,但是由于我对django相当陌生,所以我不确定如何实现整个过程,遇到很多“ X不可访问,X并非Y的属性”等问题。我在同一件事上发现了其他有用的帖子。
Django: Search form in Class Based ListView
Updating context data in FormView form_valid method?
Django CBV: Easy access to url parameters in get_context_data()?
Django class based view ListView with form
URL-parameters and logic in Django class-based views (TemplateView)
我遇到的另一个问题是,我无法使用self.kwargs访问URL中的参数,这是大多数帖子中所建议的。在我上面发布的最后一个链接中,Ngenator提到必须使用request.GET.get('parameter')访问URL参数。我用了,对我来说很好用。
通过结合所有内容,这是我拥有的经过修改的代码段。万一有人遇到与我相同的问题。
1] views.py
class SearchBookView(ListView):
template_name = 'books/search_book.html'
paginate_by = '3'
context_object_name = 'book_found'
form_class = SearchBookForm
model = Book
def get_queryset(self):
object_list = self.model.objects.all()
title = self.request.GET.get('title', None)
if title is not None and title != "":
object_list = object_list.filter(title__icontains=title)
else:
object_list = []
return object_list
def get_context_data(self):
context = super(SearchBookView, self).get_context_data()
form = self.form_class(self.request.GET or None)
context.update({
'form': form,
})
return context
2)search_book.html(模板)
{% extends "base.html" %}
{% load crispy_forms_tags %}
{% load staticfiles %}
{% load bootstrap_pagination %}
{% block title %}Search Page{% endblock %}
{% block content %}
<div class="container">
{% if form.errors %}
<p style="color: red;">
Please correct the error{{ form.errors|pluralize }} below.
</p>
{% endif %}
{% crispy form %}
{% if book_found %}
<p>Found {{ paginator.count }} book{{ book_found_no|pluralize }}.</p>
{% for book in book_found %}
<div class="wholecard">
<div style="height:170px; border:solid #111111;" class="col-md-3">
Image
</div>
<div class="card col-md-9">
<div class="card-title">"{{ book.title }}"</div>
<div>{{ book.description }}</div>
<a href="{% url 'books:detail' book.id %}" class="btn">Read More</a>
</div>
</div>
{% endfor %}
{% else %}
<p>No book matched your searching criteria.</p>
{% endif %}
{% bootstrap_paginate page_obj %}
</div>
{% endblock %}
然后我最终也使用jmcclell的bootstrap-pagination进行分页。节省了我很多时间!好东西...
您专门重写了get
方法,以便它定义自己的上下文,并且从不调用默认方法,因此自然没有默认上下文栏可用。
不要那样做;您几乎永远都不应覆盖get和post方法。您可能应该将所有表单内容直接移动到get_queryset
。
正在工作
views.py
class UserListView(ListView):
model = User
template_name = 'user_list.html'
context_object_name = 'users'
paginate_by = 10
def get_queryset(self):
return User.objects.all()
templates / user_list.html
{% if is_paginated %}
<nav aria-label="Page navigation conatiner">
<ul class="pagination justify-content-center">
{% if page_obj.has_previous %}
<li><a href="?page={{ page_obj.previous_page_number }}" class="page-link">« PREV </a></li>
{% else %}
<li class="disabled page-item"><a class="page-link">PREV !</a></li>
{% endif %}
{% for i in %}
{{ i }}
{% endfor %}
{% if page_obj.has_next %}
<li><a href="?page={{ page_obj.next_page_number }}" class="page-link"> NEXT »</a></li>
{% else %}
<li class="disabled page-item"><a class="page-link">NEXT !</a></li>
{% endif %}
</ul>
</nav>
</div>
{% endif %}