如何解析用户代理字符串? python

问题描述 投票:9回答:3
<field name="http.user_agent" showname="User-Agent: CORE/6.506.4.1 OpenCORE/2.02 (Linux;Android 2.2)\r\n" size="62" pos="542" show="CORE/6.506.4.1 OpenCORE/2.02 (Linux;Android 2.2)" value="557365722d4167656e743a20434f52452f362e3530362e342e31204f70656e434f52452f322e303220284c696e75783b416e64726f696420322e32290d0a"/>

<field name="http.user_agent" showname="User-Agent: HTC Streaming Player htc_wwe / 1.0 / htc_vivo / 2.3.5\r\n" size="67" pos="570" show="HTC Streaming Player htc_wwe / 1.0 / htc_vivo / 2.3.5" value="557365722d4167656e743a204854432053747265616d696e6720506c61796572206874635f777765202f20312e30202f206874635f7669766f202f20322e332e350d0a"/>

<field name="http.user_agent" showname="User-Agent: AppleCoreMedia/1.0.0.8C148 (iPad; U; CPU OS 4_2_1 like Mac OS X; sv_se)\r\n" size="85" pos="639" show="AppleCoreMedia/1.0.0.8C148 (iPad; U; CPU OS 4_2_1 like Mac OS X; sv_se)" value="557365722d4167656e743a204170706c65436f72654d656469612f312e302e302e38433134382028695061643b20553b20435055204f5320345f325f31206c696b65204d6163204f5320583b2073765f7365290d0a"/>

上面列出的网址示例。我想知道Python中是否有任何可用来解析用户代理的模块。我想从这些样本获取输出,例如:

Android
HTC Streaming player
ipad

如果是PC用户,我想获取Web浏览器类型。

python user-agent
3个回答
13
投票

有一个名为httpagentparser的库:

import httpagentparser
>>> s = "Mozilla/5.0 (X11; U; Linux i686; en-US) AppleWebKit/532.9 (KHTML, like Gecko) Chrome/5.0.307.11 Safari/532.9"
>>> print httpagentparser.simple_detect(s)
('Linux', 'Chrome 5.0.307.11')
>>> print httpagentparser.detect(s)
{'os': {'name': 'Linux'},
 'browser': {'version': '5.0.307.11', 'name': 'Chrome'}}

4
投票

Werkzeug内置了一个用户代理解析器。

http://werkzeug.pocoo.org/docs/quickstart/?highlight=user_agent#header-parsing

from werkzeug.test import create_environ
from werkzeug.wrappers import Request

environ = create_environ()
environ.update(HTTP_USER_AGENT=('Mozilla/5.0 (Windows NT 6.1; Win64; x64)'
    ' AppleWebKit/537.36 (KHTML, like Gecko)'
    ' Chrome/76.0.3809.100 Safari/537.36'))
request = Request(environ)

request.user_agent.browser
'chrome'

0
投票

您可以尝试使用正则表达式编写自己的内容:http://docs.python.org/library/re.html或看看这个:http://pypi.python.org/pypi/httpagentparser

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