键盘输入的动态数组填充[C]

问题描述 投票:0回答:1

我已经在C语言中实现了动态数组数据结构;我现在正在寻找一种适当的方法来从标准输入中填充数组。使用scanf()fgets()似乎不是一个好主意,因为它们的缓冲区大小在编译时是固定的,我会失去结构的动态性。因此,我正在使用getline()并为要放入数组中的每个字符动态分配内存。

我编写了此函数来填充来自stdin的两个数组:

//input arrays from keyboard
void use_input_array(){
 char *line = NULL;
 size_t len = 0;
 ssize_t read;
 puts("Enter your first ARRAY : ");

 struct dynarray *first;
 create_dynarray(&first, 1);

 while((read = getline(&line, &len, stdin)) != -1){
   if(read > 0){
    add_elem(first, line);
   }
 }
 free(line);

 char *sline = NULL;
 size_t slen = 0;
 ssize_t sread;
 puts("Enter your second ARRAY :");

 struct dynarray *second;
 create_dynarray(&second, 1);

 while((sread = getline(&sline, &slen, stdin)) != -1){
   if(sread > 0){
     add_elem(second, sline);

   }
 free(sline);    
 }
 puts("END");
}

当我执行函数时,我可以毫无问题地插入第一个字符串,但是当涉及到第二个字符串时,执行将直接结束。我不知道为什么会这样。这是一个小的可编译示例,可以更好地显示我的问题:

#include<stdio.h>
#include<stdlib.h>

typedef struct dynarray
{
   void **memory;
   size_t allocated;
   size_t used;
   int index;
} dynarray;


void create_dynarray(dynarray **array, size_t size)
{
  *array = calloc(size, sizeof **array);
  (*array)->memory = NULL;
  (*array)->allocated = 0;
  (*array)->used = 0;
  (*array)->index = -1;
}



//adds a new element at the bottom of dynarray
void add_elem(dynarray *array, void *data)
{
  size_t toallocate;
  size_t size = sizeof(void *);
  if ((array->allocated - array->used) < size){
    toallocate = array->allocated == 0 ? size : (array->allocated * 2);
    array->memory = realloc(array->memory, toallocate);
    array->allocated = toallocate;
  }

  array->memory[++array->index] = data;
  array->used = array->used + size;
}

//input arrays from keyboard
void use_input_array(){
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  puts("Enter your first ARRAY : ");

  struct dynarray *first;
  create_dynarray(&first, 1);

  while((read = getline(&line, &len, stdin)) != -1){
    if(read > 0){
     add_elem(first, line);
    }
  }
  free(line);

  char *sline = NULL;
  size_t slen = 0;
  ssize_t sread;
  puts("Enter your second ARRAY :");

  struct dynarray *second;
  create_dynarray(&second, 1);

  while((sread = getline(&sline, &slen, stdin)) != -1){
    if(sread > 0){
      add_elem(second, sline);

    }
  free(sline);    
  }
  puts("END");
}

int main(){

  use_input_array();
}


另一个问题与我的输入字符串是char的数组这一事实有关,但是我的结构被构建为无类型的,因此它需要一个空指针。我可以创建一个intdouble等数组来执行转换,但这也意味着要有一个固定的大小。但是我真的不知道从哪里开始...有什么建议吗?谢谢。

c data-structures dynamic-arrays keyboard-input
1个回答
0
投票

这样的事情可能会起作用。getline仅需要一个指针。由于为指针分配了array->memory[++array->index] = data;,因此每次迭代都需要分配更多的内存。将line设置为NULL,将len设置为零。当输入空行时,请考虑打破循环。 '\n' == line[0]。最后释放line

char *line = NULL;
size_t len = 0;
ssize_t read;
puts("Enter your first ARRAY : ");

struct dynarray *first;
create_dynarray(&first, 1);

while((read = getline(&line, &len, stdin)) != -1){
    if ( '\n' == line[0]) {
        break;
    }
    if(read > 0){
        add_elem(first, line);
        line = NULL;
        len = 0;
    }
}

puts("Enter your second ARRAY :");

struct dynarray *second;
create_dynarray(&second, 1);

while((read = getline(&line, &len, stdin)) != -1){
    if ( '\n' == line[0]) {
        break;
    }
    if(read > 0){
        add_elem(second, line);
        line = NULL;
        len = 0;

    }
}
free(line);
© www.soinside.com 2019 - 2024. All rights reserved.