从tableview到viewcontroller执行segue的问题

问题描述 投票:0回答:3

我试图用UITableView用新闻来表达一个segue。如果您推送其中一条新闻,它会对您选择的特定新闻执行segue。

这很简单,我已经做了几次......但这次我不知道我做错了什么。

NewsDetailViewController是这样的:

class NewsDetailViewController: UIViewController {

@IBOutlet weak var newsImage: UIImageView!
@IBOutlet weak var newsTitle: UILabel!
@IBOutlet weak var newsDate: UILabel!
@IBOutlet weak var newsText: UILabel!

var newsLink: String?

override func viewDidLoad() {
    super.viewDidLoad()

    // Hides the navigation bar.
    self.navigationController?.setNavigationBarHidden(true, animated: false)

}


@IBAction func closeNews(_ sender: UIButton) {
       navigationController?.popViewController(animated: true)

}

}

而NewsTableViewController中的segue是这样的:

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {

    print("you selected the row: \(indexPath.row)")
    tableView.deselectRow(at: indexPath, animated: true)
    self.performSegue(withIdentifier: "goToNewsDetail", sender: self)

}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

    if segue.identifier == "goToNewsDetail" {

        if let destination = segue.destination as? NewsDetailViewController {

            destination.newsLink = "whateverlink"
            destination.newsTitle.text = "whatevertitle"

        }

    }

}

和线:destination.newsLink = "whateverlink"完美的工作。

但是这条线:destination.newsTitle.text = "whatevertitle"投掷a

致命错误:在隐式解包Optional值时意外发现nil。

我不知道如果继续下去会怎么样。尝试初始化目标中的其余标签时会发生同样的问题。

ios swift uitableview uistoryboardsegue
3个回答
1
投票

这条线就是问题所在

destination.newsTitle.text = "whatevertitle"

不访问目标vc的出口,因为它们尚未加载发送字符串并将其分配给目标vc中的标签

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "goToNewsDetail" {
            if let destination = segue.destination as? NewsDetailViewController {
                destination.newsLink = "whateverlink"
                destination.toSend = "whatevertitle"
        }
    }
}
class NewsDetailViewController: UIViewController {
    @IBOutlet weak var newsTitle:UILabel!
    var toSend = ""
    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
        self.newsTitle.text = toSend
    }
}

1
投票

prepareForSegue方法中,newsTitle标签仍未初始化,因此它是nil

通常,您不应在prepareForSegue中设置目标VC的视图属性。您应该在newsTitleText中声明一个NewsDetailViewController属性:

var newsTitleText: String!

并设置此属性:

destination.newsTitleText = "whatevertitle"

然后在newsTitle.text中设置viewDidLoad

override func viewDidLoad() {
    super.viewDidLoad()

    // Hides the navigation bar.
    self.navigationController?.setNavigationBarHidden(true, animated: false)
    newsTitle.text = newsTitleText
}

1
投票

当调用prepare(for:sender:)方法时,NewsDetailViewController尚未加载视图,因此您无法在标签上设置文本。你想要做的是在NewsDetailViewController上创建另一个属性,例如var newsTitleText: String?。然后在viewDidLoad你可以打电话给newsTitle.text = newsTitleText

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