php mysql项目中的数据库连接错误[重复]

Question

此问题已经在这里有了答案：

Cannot connect to MySQLi in PHP?（5个答案）

关闭6分钟前。

<?php 
                        $conn = new mysqli("localhost","root","","sdbms");
                        if($conn->connect_error )
                        {
                            die("connection failed: ". $conn->connect_error);
                        }
                        $sql="SELECT eid, fname, lname,jobType,salary,dname,E.did 
                        FROM employee E, department d
                        WHERE E.did=d.did";
                        $result = mysqli_query($conn, $sql);
                        if($result->num_rows > 0)
                        {while($row = mysqli_fetch_array($result)){
                             echo "<tr><td>".$row[0]."</td><td>".$row[1]."</td><td>".$row[2]."</td><td>".$row[3]."</td><td>".$row[4]."</td><td>".$row[5]."</td>";
                            }       
                        }
                    ?> 

发生此错误：connect_error）{die（“连接失败：”。$ conn-> connect_error）; } $ sql =“ SELECT eid，fname，lname，jobType，salary，dname，E.did来自雇员E，部门d WHERE E.did = d.did”; $结果= mysqli_query（$ conn，$ sql）; if（$ result-> num_rows> 0）{while（$ row = mysqli_fetch_array（$ result））{echo“”; }}？>

[[谁愿意用我的整个项目来帮助我。

Answer 1

您的SQL语句中有很多错误

<?php 
$conn = new mysqli("localhost","root","","sdbms");
if($conn->connect_errno){  
    die("connection failed: ".$conn->connect_error);
}

// SQL Statement looks malformed.
$sql="SELECT eid, fname, lname,jobType,salary,dname,E.did 
    FROM employee E, department d
    WHERE E.did=d.did";
$result = mysqli_query($conn, $sql);
if($result->num_rows > 0){?>
    <table border="0" width="100%">
    <?php while($row = mysqli_fetch_assoc($result){?>
        <tr>
            <td><?php //echo $row['some_index']; ?></td>
            <td><?php //echo $row['some_index']; ?></td>
            <td><?php //echo $row['some_index']; ?></td>
            <td><?php //echo $row['some_index']; ?></td>
            <td><?php //echo $row['some_index']; ?></td>
            <td><?php //echo $row['some_index']; ?></td>
        </tr>
    <?php } ?>
    </table>
<?php } ?>