如何删除多余的双引号,而不是使用bash脚本在一行文本中打开和关闭双引号

问题描述 投票:0回答:3

我有一个文本文件,我想将其复制到CSV文件中,然后将该CSV文件复制到PostgreSQL表中。

我的输入文本文件是(old_sample.txt),

SVCOP,"12980","2019"0627","1DEX","LUBE, OIL & FILTER - DEXOS "1"","I","0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS ''1''","91","LANE","LANE","L","LA MERE","125.00","125.00","","0.00","0.00","0","0","0","||||||||||||||||||||||||","N"

我必须使用下面的代码

cat old_sample.txt
printf "\n"
echo "____________________________________"
printf "\n"
cat old_sample.txt | sed ': again
s/\("[^",]*\)"\([^",]*"\)/\1\2/g
t again
s/""/"/g' 

输出是

SVCOP,"12980","2019"0627","1DEX","LUBE, OIL & FILTER - DEXOS "1"","I","0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS ''1''","91","LANE","LANE","L","LA MERE","125.00","125.00","","0.00","0.00","0","0","0","||||||||||||||||||||||||","N"
SVCOP,"12980","20190627","1DEX","LUBE, OIL & FILTER - DEXOS "1","I","0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS ''1''","91","LANE","LANE","L","LA MERE","125.00","125.00",","0.00","0.00","0","0","0","||||||||||||||||||||||||","N"

问题是"LUBE, OIL & FILTER - DEXOS "1""

“ 1”这个双引号由于逗号而没有被删除,但是在双引号中却存在“ 2019” 0627“,所以我想删除用开和闭双引号括起来的字符串中的所有双引号。否则,它将显示数据库错误。

这是我的代码

nl -ba -nln -s, < old_sample.txt | sed ': again
                                      s/\("[^",]*\)"\([^",]*"\)/\1\2/g
                                      t again' | grep 'SVCPTS' > old_sample.csv
psql_local <<SQL || die "Failed to import parts data"
        \copy sample_table from 'old_sample.csv' with (format csv, header false)
SQL 

我的目标输出是

SVCOP,"12980","20190627","1DEX","LUBE, OIL & FILTER - DEXOS 1","I","0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS ''1''","91","LANE","LANE","L","LA MERE","125.00","125.00","","0.00","0.00","0","0","0","||||||||||||||||||||||||","N"
regex bash postgresql shell pattern-matching
3个回答
0
投票

就我个人而言,我将寻求实用程序。我认为您也许可以通过找到正确的RegEx来实现它-但最终可能会变得非常复杂。

使用csvkit之类的东西-具体来说,the csvformat command似乎容易得多。如果将来您需要将此脚本与其他数据一起重用(在某些字段中可能会有换行符,或者可能需要考虑其他情况),也会更加可靠。


0
投票

请您尝试以下操作:

str=$(<odd_sample.txt)          # slurps the file into a variable "str"
while true; do                  # infinite loop
   str2=$(sed 's/\([^,]\)"\([^,]\)/\1\2/g' <<< "$str")
   [[ $str2 = $str ]] && break  # if there is no change, exit the loop
   str="$str2"                  # update "str" for next iteration
done
echo "$str"

输出:

SVCOP,"12980","20190627","1DEX","LUBE, OIL & FILTER - DEXOS 1","I","0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS ''1''","91","LANE","LANE","L","LA MERE","125.00","125.00","","0.00","0.00","0","0","0","||||||||||||||||||||||||","N"
  • 正则表达式\([^,]\)"\([^,]\)匹配双引号,并把它括起来通过non-逗号。
  • 它一直循环直到所有多余的双引号都被删除。
  • 上面的脚本将适用于所提供的示例,但可能并不健壮足够用于任意输入。建议介绍一种工具如chrisputnam9所建议的那样,它能够解析csv文件以获得可靠的结果。

0
投票

无法在一个命令中完成,所以我做到了

 $ sed "s/['\"]//g; s/,/\",\"/g; s/\",\" /, /g; s/,,/,\"\",/g; s/$/\"/; s/\"//" file
SVCOP,"12980","20190627","1DEX","LUBE, OIL & FILTER - DEXOS 1","I,0.4","0.4","15.95","10.80","0.00","0.00","0.00","0.00","0.00","0.00","38.03","30.17","53.98","40.97","FULL SYNTHETIC MOTOR OIL.","LUBE, OIL & FILTER - DEXOS 1","91","LANE","LANE","L,LA MERE","125.00","125.00,"",0.00","0.00","0,0","0,||||||||||||||||||||||||","N"
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