python - 根据部分字符串在列表中查找索引位置

Question

mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]

我需要包含'aa'的所有项目的索引位置。我在将enumerate（）与部分字符串匹配相结合时遇到了麻烦。我甚至不确定我是否应该使用枚举。

我只需要返回指数位置：0,2,5

Answer 1

indices = [i for i, s in enumerate(mylist) if 'aa' in s]

Answer 2

你使用enumerate()的想法是正确的。

indices = []
for i, elem in enumerate(mylist):
    if 'aa' in elem:
        indices.append(i)

或者，作为列表理解：

indices = [i for i, elem in enumerate(mylist) if 'aa' in elem]

Answer 3

没有enumerate()：

>>> mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]
>>> l = [mylist.index(i) for i in mylist if 'aa' in i]
>>> l
[0, 2, 5]

Answer 4

spell_list = ["Tuesday", "Wednesday", "February", "November", "Annual", "Calendar", "Solstice"]

index=spell_list.index("Annual")
print(index)