请帮助我
致命错误:未捕获错误:在 C:\xampp\htdocs inal_program\php\loged_in.php:9 中找不到类“mysqli_connect” .php 第 9 行
我试图删除行开头的分号 (;) 以取消注释:
extension=mysqli
但是我的 php 代码仍然没有连接到我的数据库 phpmyadmin 它只显示此代码
致命错误:未捕获错误:在 C:\xampp\htdocs inal_program\php\loged_in.php:9 中找不到类“mysqli_connect” .php 第 9 行
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "management";
$conn = new mysqli_connect($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if (isset($_POST['login'])) {
// Get username and password from form data and validate them
$username = $_POST['username'];
$password = $_POST['password'];
// Check if the username and password are correct
// In this example, we're using a MySQLi prepared statement to protect against SQL injection
$stmt = $conn->prepare("SELECT * FROM users WHERE username = ? AND password = ?");
$stmt->bind_param("ss", $username, $password);
$stmt->execute();
$result = $stmt->get_result();
if ($result->num_rows == 1) {
// If the user is authenticated, set the user's login status to true
// In this example, we're just using a session variable to store the login status
$_SESSION['logged_in'] = true;
}
}
if (isset($_SESSION['logged_in']) && $_SESSION['logged_in'] == true) {
// If the user is logged in, display the success container by changing the CSS display property
echo '<style>.success-container { display: block; }</style>';```
没有任何类称为
mysqli_connect
。根据 documentation,建立数据库连接是 procedural 风格。
请比较(取自同一页面中的示例):
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'my_db');
$mysqli = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
你正在尝试使用 OOP,所以选择前者。