为什么我收到错误“TypeError: ResourceModel.__init__() missing 4 required positional arguments: 'width' 'height' 'n_agents' & 'n_resources''？

Question

我正在尝试使用 mesa 制作多代理系统，但代码无法运行。我不断收到同样的错误，但据我所知，我添加了正确的参数。

from mesa import Agent, Model
from mesa.space import MultiGrid
from mesa.time import RandomActivation
from mesa.visualization.modules import CanvasGrid
from mesa.visualization.ModularVisualization import ModularServer
from mesa import DataCollector

class Resource(Agent):
    def __init__(self, unique_id, model):
        super().__init__(unique_id, model)
        self.amount = 10
        
    def step(self):
        pass

class ResourceAgent(Agent):
    def __init__(self, unique_id, model):
        super().__init__(unique_id, model)
        self.resources = 0
        
    def step(self):
        # Find neighboring resources
        neighbors = self.model.grid.get_neighbors(self.pos, moore=True, include_center=False)
        resources = [agent for agent in neighbors if isinstance(agent, Resource)]
        
        # Collect resources
        for resource in resources:
            self.resources += resource.amount
            self.model.grid.remove_agent(resource)
        
        # Move randomly
        x, y = self.pos
        dx, dy = self.random.choice([-1, 0, 1]), self.random.choice([-1, 0, 1])
        self.model.grid.move_agent(self, (x+dx, y+dy))


class ResourceModel(Model):
    def __init__(self, width, height, n_agents, n_resources):
        self.grid = MultiGrid(width, height, torus=True)
        self.schedule = RandomActivation(self)

        # Create resources
        for i in range(n_resources):
            resource = Resource(i, self)
            x, y = self.random.randrange(width), self.random.randrange(height)
            self.grid.place_agent(resource, (x, y))
            self.schedule.add(resource)

        # Create agents
        for i in range(n_agents):
            agent = ResourceAgent(n_resources + i, self)
            x, y = self.random.randrange(width), self.random.randrange(height)
            self.grid.place_agent(agent, (x, y))
            self.schedule.add(agent)

        # Create a grid visualization
        self.grid_viz = CanvasGrid(lambda: self.grid.grid, width, height, 500, 500)

        # Run the model
        self.running = True
        self.datacollector = DataCollector(
            {"Resources": lambda m: self.count_resources()},
            agent_reporters={"Resources": lambda a: a.resources},
        )

    def count_resources(self):
        return len([agent for agent in self.schedule.agents if isinstance(agent, Resource)])

    def step(self):
        self.schedule.step()
        self.datacollector.collect(self)


# Create a ResourceModel object
model = ResourceModel(width=10, height=10, n_agents=5, n_resources=10)
server = ModularServer(ResourceModel, [model.grid_viz], "Resource Model")
server.launch()

我尝试用 model = ResourceModel(10, 10, 5, 10) 重写 model = ResourceModel(width=10, height=10, n_agents=5, n_resources=10) 但这当然没有区别。

Answer 1

您缺少

model_params

的

ModularServer()

参数，因此它在调用

ResourceModel()

时没有传递所需的参数。

server = ModularServer(ResourceModel, [model.grid_viz], "Resource Model", model_params={'width': 10, 'heigh': 10, 'n_agents': 5, 'n_resources': 10})