3D Voronoi图:“半径与发生器不一致”

问题描述 投票:0回答:1

我想计算通过立体视觉获得的3d点云的“密度”。

我像https://docs.scipy.org/doc/scipy/reference/generated/scipy.spatial.SphericalVoronoi.html一样实现了3D Voronoi图

结果在许多不同的幅度上都提高了ValueError("Radius inconsistent with generators.")(我尝试了很多)

我的点云示例为:

[[ 0.63492548  0.10921954  0.12711886]
 [ 0.14530358  0.02687934 -0.0357723 ]
 [ 0.16594444  0.02741969  0.04187516]
 [ 0.69606036  0.06983382 -0.04752853]
 [ 0.31324029 -0.10254659 -0.06861327]
 [ 0.14450935 -0.07421818 -0.07544217]
 [ 0.66847998  0.08925844  0.2252084 ]
 [ 0.17888862  0.02983894  0.01823071]
 [ 0.65812635  0.1793924  -0.00177464]
 [ 0.7880221   0.25733843 -0.22293468]]

a)我该如何解决?

b)而且我的点云也在变化,这取决于我所在的位置(点云是真实世界的坐标)。因此,我需要一个自适应指标来输入半径,具体取决于我认为的点云本身?

还有想法?非常感谢!:)

3d diagram voronoi radius
1个回答
0
投票
def voronoi_volumes(points):
    v = Voronoi(points)
    vol = np.zeros(v.npoints)
    for i, reg_num in enumerate(v.point_region):
        indices = v.regions[reg_num]
        if -1 in indices: # some regions can be opened
            vol[i] = np.inf
        else:
            try:
                vol[i] = ConvexHull(v.vertices[indices]).volume
            except:
                vol[i] = np.inf
    return vol
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