Sql将楼层应用于日期时间,其中楼层不是标准的,例如每2小时,每2天等

问题描述 投票:0回答:1

目标:Sql将楼层应用于日期时间,其中楼层不是标准的,例如每隔2小时,每3天一次。而不是标准每小时,每天等。

通用目的:为每个收集期间的数据进行比较。当收集期间大于标准时间单位时。同时保留Datetime类型的好处。

转换示例:

将日期时间设为2小时

+==========================+=======================+
|        WhenCreated       |       Time_Slot       |
+==========================+=======================+
|   2019-02-28 00:34:00    | 2019-02-28 00:00:00   |
+--------------------------+-----------------------+
|   2019-02-28 01:34:00    | 2019-02-28 00:00:00   |
+--------------------------+-----------------------+
|   2019-02-28 02:00:00    | 2019-02-28 02:00:00   |
+--------------------------+-----------------------+
|   2019-02-28 02:20:00    | 2019-02-28 02:00:00   |
+--------------------------+-----------------------+
|   2019-02-28 03:59:00    | 2019-02-28 02:00:00   |
+--------------------------+-----------------------+

当前解决方案

在select语句中将根据[WhenCreated]创建一个新列[Time_Slot]:

left(convert(varchar(30), WhenCreated, 102),4) + '-' + left(right(convert(varchar(30), WhenCreated, 102),5),2) + '-' + right(convert(varchar(30), WhenCreated, 102),2) + ' ' +
    case
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('00','01') then '00:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('02','03') then '02:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('04','05') then '04:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('06','07') then '06:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('08','09') then '08:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('10','11') then '10:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('12','13') then '12:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('14','15') then '14:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('16','17') then '16:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('18','19') then '18:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('20','21') then '20:00:00.000'
        when left(cast(cast(WhenCreated as time) as varchar(30)),2) in ('22','23') then '22:00:00.000'
    end as [Time_Slot]

当前的挑战:当前的解决方案有效,但它很混乱。必须有一个更简单的方法。那么有什么更好的方法呢?

编辑:表中的修复错误。

sql sql-server datetime floor
1个回答
1
投票

将日期解构为其零件,然后使用必要的零件重新构造它,调整需要铺设的零件。

要将整数值置于乘数,只需除以乘数并再次乘以它。这依赖于整数除法截断除法结果,例如5 / 2 = 2,所以5 / 2 * 2 = 4,即截断为2的倍数。

因此,将WhenCreated值降至2小时的倍数:

DATETIMEFROMPARTS ( YEAR(WhenCreated), MONTH(WhenCreated), DAY(WhenCreated),
                    DATEPART(HOUR, WhenCreated) / 2 * 2, /*min*/0, /*sec*/0, /*milli*/0 )
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