使用WarpAffine()将Emgu.CV.Image向右移动。

Question

我的目标是，将一个图像向右移动x个像素。我想这可以通过使用WarpAffine来实现。这至少是我的研究告诉我的。我使用了相当多的不同方法，比如。

CvInvoke.WarpAffine(realImage, transformedImage, transformationMatrix, new Size(realImage.Size);

//or while m is the Mat used to create realImage
transImage.WarpAffine(m,Emgu.CV.CvEnum.Inter.Area,Emgu.CV.CvEnum.Warp.Default,Emgu.CV.CvEnum.BorderType.Default,new Gray());

我得到的是Exeption:

Exception thrown: 'Emgu.CV.Util.CvException' in Emgu.CV.Platform.NetStandard.dll
[ WARN:0] global E:\bb\cv_x86\build\opencv\modules\videoio\src\cap_msmf.cpp (436) `anonymous-namespace'::SourceReaderCB::~SourceReaderCB terminating async callback

我想是我用错了方法 但网上没有合适的例子供我学习。有谁有简洁的方法给我解释一下吗？

先谢谢你了!

Answer 1

如果你是向右移动像素x数量，我假设左边会有黑色的空像素？如果是这样，你可以创建一个ROI，并切断右侧的一些像素，因为你正在将所有像素向右移动，并将图像复制到另一个图像。

//The image that you want to shift pixels with
Image<Bgr, byte> inputImage = new Image<Bgr, byte>(1000, 1000);

//The output image
Image<Bgr, byte> image = new Image<Bgr, byte>(990, 1000);

//Create the roi, with 10 pixels cut off from the right side because of the shift
inputImage.ROI = new Rectangle(0, 0, inputImage.Width - 10, inputImage.Height);

inputImage.CopyTo(image);

CvInvoke.ImShow("The Output", image);
CvInvoke.WaitKey(0);

EDIT

现在让我们假设你想在图片的左侧也保留那条黑色的条纹。这样做与上面的代码非常相似，只是做了一些修改。

//The image that you want to shift pixels with
Image<Bgr, byte> inputImage = new Image<Bgr, byte>(1000, 1000);

//The output image
Image<Bgr, byte> image = new Image<Bgr, byte>(1000, 1000);

//Create the roi, with 10 pixels cut off from the right side because of the shift
inputImage.ROI = new Rectangle(0, 0, inputImage.Width - 10, inputImage.Height);

//The image we want to shift, the same one we created a ROI with, 
//has the dimensions 990 X 1000 and the output image has 
//dimensions of 1000 x 1000. Unfortunately, in order to paste 
//an image onto another image, they need to be the same dimensions. 
//How do we do this? We must create an ROI with the output image 
//that has the same dimensions as the input image. 

image.ROI = new Rectangle(10, 0, image.Width, image.Height);

//Now we can past the image onto the output because the dimensions match
inputImage.CopyTo(image);

//Inorder to make our output seem normal, we must empty the ROI of the output image
image.ROI = Rectangle.Empty;

CvInvoke.ImShow("The Output", image);
CvInvoke.WaitKey(0);