我指的是Scala implicit conversion for object发布的答案
sealed trait Command {
val typeName: String
//This is required for implicit conversion.
override def toString: String = typeName
}
object SendMessageCommand extends Command {
override val typeName: String = "send_message"
}
object AddMessageCommand extends Command {
override val typeName: String = "add_message1"
}
object UpdateMessageCommand extends Command {
override val typeName: String = "update_message"
}
object DeleteMessageCommand extends Command {
override val typeName: String = "delete_message"
}
//List of commands.
implicit val cmds: List[Command] = List(SendMessageCommand, AddMessageCommand, UpdateMessageCommand, DeleteMessageCommand)
//Convert given type T into type U.
implicit def convert[T, U](s: T)(implicit list: List[U]): Option[U] = {
list.find(_.toString == s.toString)
}
implicit val convert3: Command => String =
(v: Command) => v.typeName
val res1:String = UpdateMessageCommand
val res: Option[Command] = "add_message1"
我创建了我的新转换器convert3
,它转换Command => String。上面的工作,但我不知道为什么用户有隐藏转换的字符串
//This is required for implicit conversion.
override def toString: String = typeName
这在帖子中回答:
注意:因为我通过将它们转换为字符串来比较转换中的两个类型实例,所以我必须在Command中覆盖此用例的toString方法。
因为它是为通用T
和U
编写的(并且它们没有边界),所以作者不能调用typeName
。
但老实说,首先定义一个隐含的转换(convert
,而不是convert3
)是一个坏主意。