我正在尝试查找每个工作日每个room_id的最长连续时间。我想将工作日转换为其整数表示形式(0代表星期日,1代表星期一,等等)。
到目前为止我所拥有的:
create or replace function iweekday(weekday varchar(9))
returns int as $$
DECLARE iw INT;
begin
select iw= CASE weekday
WHEN 'Monday' THEN 1
WHEN 'Tuesday' THEN 2
WHEN 'Wednesday' THEN 3
WHEN 'Thursday' THEN 4
WHEN 'Friday' THEN 5
WHEN 'Saturday' THEN 6
WHEN 'Sunday' THEN 0
END;
end;
$$ language plpgsql;
create or replace function fourpointnine()
returns table (room_id character(7), iw int, start_time int,end_time int) as $$
DECLARE iw INT;
begin
with recursive cte as(
select l.room_id, l.weekday, l.start_time, l.end_time
from "learningactivity" l
union all
select l.room_id, l.weekday, cte.start_time, l.end_time
from cte join "learningactivity" l on l.room_id=cte.room_id and l.weekday=cte.weekday and cte.end_time=l.start_time
), cte2 as(
select *, row_number() over (partition by cte.room_id order by EXTRACT(EPOCH FROM cte.end_time - cte.start_time)/3600 desc ) as rn
from cte
)
select distinct cte2.room_id, iweekday(cte2.weekday), cte2.start_time, cte2.end_time
from cte2
where rn=1
group by cte2.room_id, iweekday(cte2.weekday), cte2.start_time, cte2.end_time;
end;
$$ language plpgsql;
但是我收到此错误:
ERROR: query has no destination for result data HINT: If you want to discard the results of a SELECT, use PERFORM instead. CONTEXT: PL/pgSQL function iweekday(character varying) line 4 at SQL statement
如何正确执行?
立即错误可以用RETURN QUERY
修复。参见:
但是不要打扰,从一开始,PL / pgSQL函数就显得过于刻板。
您的助手功能通过这种方式更简单,更便宜:CREATE OR REPLACE FUNCTION iweekday(weekday text)
RETURNS int LANGUAGE sql IMMUTABLE PARALLEL SAFE AS
$func$
SELECT CASE weekday
WHEN 'Monday' THEN 1
WHEN 'Tuesday' THEN 2
WHEN 'Wednesday' THEN 3
WHEN 'Thursday' THEN 4
WHEN 'Friday' THEN 5
WHEN 'Saturday' THEN 6
WHEN 'Sunday' THEN 0
END
$func$;
([PARALLEL SAFE
仅用于Postgres 9.6或更高版本。]
最重要的是,它可以是inlined。相关:
WITH RECURSIVE cte AS (
SELECT l.room_id, l.weekday, l.start_time, l.end_time
FROM learningactivity l
UNION ALL
SELECT l.room_id, l.weekday, c.start_time, l.end_time
FROM cte c
JOIN learningactivity l ON l.room_id = c.room_id
AND l.weekday = c.weekday
AND l.start_time = c.end_time
)
SELECT DISTINCT ON (1, 2)
c.room_id, iweekday(c.weekday) AS iw, c.start_time, c.end_time
FROM cte c
ORDER BY 1, 2, c.start_time - c.end_time;
如果您坚持使用功能:
CREATE OR REPLACE FUNCTION fourpointnine()
RETURNS TABLE (room_id text, iw int, start_time int, end_time int)
LANGUAGE sql AS
$func$
-- paste query from above
$func$;
请勿使用数据类型character(N)
。参见: