以编程方式创建触发器时,重载的构造函数错误

问题描述 投票:0回答:2

我想创建一个流程,当人们提交表单时,我只填写信息(并不是每个字段都需要填写)。找到了代码(http://www.labnol.org/internet/google-docs-email-form/20884/),根据作者进行了所有操作,但对我没有用。我不是编码专家,因此需要您的帮助。

这里是代码:

function Initialize() {

  var triggers = ScriptApp.getScriptTriggers();

  for(var i in triggers) {
    ScriptApp.deleteTrigger(triggers[i]);
  }

  ScriptApp.newTrigger("SendGoogleForm")
  .forSpreadsheet(SpreadsheetApp.getActiveSpreadsheet())
  .onFormSubmit()
  .create();

}

function SendGoogleForm(e) 
{  
  try 
  {      
    // You may replace this with another email address
    var email = "[email protected]";

    // Optional but change the following variable
    // to have a custom subject for Google Form email notifications
    var subject = "New Driver Application Arrived";  

    var s = SpreadsheetApp.getActiveSheet();
    var columns = s.getRange(1,1,1,s.getLastColumn()).getValues()[0];    
    var message = "";    

    // Only include form fields that are not blank
    for ( var keys in columns ) {
      var key = columns[keys];
      if ( e.namedValues[key] && (e.namedValues[key] != "") ) {
        message += key + ' :: '+ e.namedValues[key] + "\n\n"; 
      }
    }

    // This is the MailApp service of Google Apps Script
    // that sends the email. You can also use GmailApp for HTML Mail.

    MailApp.sendEmail(email, subject, message); 

  } catch (e) {
    Logger.log(e.toString());
  }

}

这是运行初始化进行测试时得到的:

Cannot call overloaded constructor forSpreadsheet with parameters
(null) because there is more than one matching constructor signature:
interface SpreadsheetTriggerBuilder forSpreadsheet(Spreadsheet)
interface SpreadsheetTriggerBuilder forSpreadsheet(String) (line 12,
file "Code")
google-apps-script google-form
2个回答
1
投票

[将代码添加到正在收集响应的Google Spreadsheet的脚本编辑器中,而不是在表单编辑器中。[source]

说明:错误消息表明forSpreadsheet()的参数为(null)。您输入了SpreadsheetApp.getActiveSpreadsheet(),因此评估为null。该方法仅适用于电子表格绑定的脚本。


0
投票

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