我是java的新手,这可能听起来真的很愚蠢但是!假设你的电脑里有这个txt文件
The_txt.txt
安东尼
Anthony [email protected]
01234567891
地点
玛丽
1234561234
LOCATION2
乔治
1234512345
LOCATION3
我想用这个txt做的是,我提示用户插入一个电话号码,所以如果用户提供Maria的电话号码(1234561234),程序将输出
玛丽
1234561234
LOCATION2
我完成这项任务的代码:
private static void Search_Contact_By_Phone(File file_location){
Scanner To_Be_String = new Scanner(System.in);
String To_Be_Searched = To_Be_String.nextLine();
System.out.println("\n \n \n");
BufferedReader Search_Phone_reader;
try {
Search_Phone_reader = new BufferedReader(new FileReader (file_location));
String new_line = Search_Phone_reader.readLine();
while (new_line != null) {
if (To_Be_Searched.equals(new_line)){
for (int i=0;i<=3;i++){
System.out.println(new_line);
new_line = Search_Phone_reader.readLine();
}
break;
}
new_line = Search_Phone_reader.readLine();
}
Search_Phone_reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
先感谢您!!!
package com.mycompany.io;
import java.io.BufferedReader;
import java.io.IOException;
import java.nio.charset.StandardCharsets;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.List;
public class Main {
public static void main(String[] args) throws IOException {
// For a small file
Path path = Paths.get("The_txt.txt");
String toBeSearched = "1234512345";
List<String> lines = Files.readAllLines(path, StandardCharsets.UTF_8);
// Better performance if i starts at 2 and i += 4
for (int i = 0; i < lines.size(); i++) {
if (lines.get(i).equals(toBeSearched)) {
System.out.println(lines.get(i - 2));
System.out.println(lines.get(i - 1));
System.out.println(lines.get(i));
System.out.println(lines.get(i + 1));
}
}
// Else
try (BufferedReader reader = Files.newBufferedReader(path, StandardCharsets.UTF_8)) {
String line1;
while ((line1 = reader.readLine()) != null) {
String line2 = reader.readLine();
String line3 = reader.readLine();
if (line3.equals(toBeSearched)) {
// Found
System.out.println(line1);
System.out.println(line2);
System.out.println(line3);
System.out.println(reader.readLine());
break;
} else {
reader.readLine();
}
}
}
}
}