从字符串中的数组键替换匹配的字符串

Question

我的目标是在一个字符串中找到一个假定的数组的键，然后在该字符串中，用数组中匹配的键替换这些键。

我有一个有用的小函数，它可以在2个定界符之间找到我的所有字符串（沙盒链接：https://repl.it/repls/UnlinedDodgerblueAbstractions：]

function findBetween( $string, $start, $end )
{
    $start = preg_quote( $start, '/' );
    $end = preg_quote( $end, '/' );

    $format = '/(%s)(.*?)(%s)/';

    $pattern = sprintf( $format, $start, $end );

    preg_match_all( $pattern, $string, $matches );

    $number_of_matches = is_string( $matches[2] ) ? 1 : count( $matches[2] );

    if( $number_of_matches === 1 ) {
        return $matches[2];
    }

    if( $number_of_matches < 2 || empty( $matches ) ) {
        return False;
    }

    return $matches[2];
}

示例：

findBetween( 'This thing should output _$this_key$_ and also _$this_one$_ so that I can match it with an array!', '_$', '$_')

应该像这样返回一个带有值['this_key', 'this_one']的数组。问题是，我该如何接受这些并将其替换为关联数组的值？

假设我的数组是这个：

[
    'this_key' => 'love',
    'this_one' => 'more love'
];

我的输出应该是这个：

This thing should output love and also more love so that I can match it with an array!

我该如何实现？

Answer 1

希望这可以解决您对问题的回答！

$items['this_key'] = 'love';
$items['this_one'] = 'more love';

$string = 'This thing should output _$this_key$_ and also _$this_one$_ so that I can match it with an array!';

$this_key = $items['this_key'];
$this_one = $items['this_one'];
$string = str_replace('_$this_key$_',$this_key,$string);
$string = str_replace('_$this_one$_',$this_one,$string);

echo  $string;

Answer 2

[这个问题比正则表达式更容易用strtr解决。我们可以使用strtr在array_map的键周围添加array_map和$start值，然后使用$end进行替换：

$replacements

输出：

strtr

$str = 'This thing should output _$this_key$_ and also _$this_one$_ so that I can match it with an array!';
$replacements = [
    'this_key' => 'love',
    'this_one' => 'more love'
];
$start = '_$';
$end = '$_';
$replacements = array_combine(array_map(function ($v) use ($start, $end) { return "$start$v$end"; }, array_keys($replacements)), $replacements);
echo strtr($str, $replacements);