AccessibilityService：可以使用鼠标在远程智能手机屏幕上绘制密码吗？

Question

我在一个类似于Team View QuickSupport的项目中工作，我想知道AccessibilityService是否允许在远程屏幕上执行滑动，以便能够绘制保护设备的密码？

我来尝试以下代码，但没有成功。到目前为止，所有发生的事情都是android代码上的异常，它说：

java.lang.IllegalStateException：尝试向手势添加过多笔划

这里：

gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));

当前的Java代码是这样的：

    if (xline.contains("mouseswipescreen")) {

     String coords = xline.replace("mouseswipescreen", "");

     String[] tokens = coords.split(Pattern.quote("<|>"));

               float x = parseFloat(tokens[0]);
               float y = parseFloat(tokens[1]);
               String cmd = tokens[2];

     MyAccessibility.instance.Swipte((int) x, (int) y, 50, cmd);
 }

---

GestureDescription.Builder gestureBuilder;
Path path;

public void Swipte(int x, int y, int time, String command) {

    if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
        System.out.println(" ======= Swipte =======");

        if (command.equalsIgnoreCase("start")) {

            gestureBuilder = new GestureDescription.Builder();
            path = new Path();

            path.moveTo(x, y);

        } else if (command.equalsIgnoreCase("move")) {

            path.lineTo(x, y);
            gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));

        } else if (command.equalsIgnoreCase("dispatch")) {

            dispatchGesture(gestureBuilder.build(), new GestureResultCallback() {
                @Override
                public void onCompleted(GestureDescription gestureDescription) {
                    System.out.println("SWIPTE Gesture Completed :D");
                    super.onCompleted(gestureDescription);
                }
            }, null);
        }
    }

}

现在更改此代码以执行保持这种方式的滑动屏幕：

public void Swipte(int x1, int y1, int x2, int y2, int time){

        if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {

            System.out.println(" ======= Swipte =======");

            GestureDescription.Builder gestureBuilder = new GestureDescription.Builder();
            Path path = new Path();
            path.moveTo(x1,y1); // "mousedown"
            path.lineTo(x2,y2); // until last position found in "mousemove"

            gestureBuilder.addStroke(new GestureDescription.StrokeDescription(path, 0, time));
            dispatchGesture(gestureBuilder.build(), new GestureResultCallback() {
                @Override
                public void onCompleted(GestureDescription gestureDescription) {
                    System.out.println("SWIPTE Gesture Completed :D");
                    super.onCompleted(gestureDescription);
                }
            }, null);
        }

    }

结果是这样的：

看到这是一个错误的密码。

最后是代码（Delphi），它基于上面的第一个Java代码发送坐标（qazxsw poi）：

reference

Answer 1

好吧，我回答我自己的问题，已经是

 private
    { Private declarations }
    fDown: Boolean;
    fPO: TPoint;
  public
    { Public declarations }
  end;

  ...

procedure TForm2.Image1MouseDown(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);
var
  Index, XTouch, YTouch, RXCoord, RYCoord: Integer;
  List: TStrings;
  RScreen, Start: String;
begin
  Index := Form1.ListView1.ItemIndex;
  if Index = -1 then
    Exit;

    List := TStringList.Create;
    RScreen := Form1.ListView1.Selected.SubItems[6]; // Remote screen resolution

    try
      ExtractStrings(['x'], [], PChar(RScreen), List); // Ex: my smartphone is 1920x1080
      RYCoord := StrToInt(List[0]);                    // 1920 (height)
      RXCoord := StrToInt(List[1]);                    // 1080 (width)
    finally
      List.Free;
    end;

    XTouch := Round((X / Image1.Width) * RXCoord);
    YTouch := Round((Y / Image1.Height) * RYCoord);

    fPO := Point(XTouch, YTouch);
    Start := 'start';
    fDown := true;

    Form1.ServerSocket1.Socket.Connections[Index].SendText(format('mouseswipescreen%d<|>%d<|>%s'#13#10, [fPO.X, fPO.Y, Start]));

  end;
end;

procedure TForm2.Image1MouseMove(Sender: TObject; Shift: TShiftState;
  X, Y: Integer);
var
  Index, XTouch, YTouch, RXCoord, RYCoord: Integer;
  List: TStrings;
  RScreen, Move: String;
begin

  Index := Form1.ListView1.ItemIndex;
  if Index = -1 then
    Exit;

  List := TStringList.Create;
  RScreen := Form1.ListView1.Selected.SubItems[6]; // Remote screen resolution

  try
    ExtractStrings(['x'], [], PChar(RScreen), List); // Ex: my smartphone is 1920x1080
    RYCoord := StrToInt(List[0]);                    // 1920 (height)
    RXCoord := StrToInt(List[1]);                    // 1080 (width)
  finally
    List.Free;
  end;

  XTouch := Round((X / Image1.Width) * RXCoord);
  YTouch := Round((Y / Image1.Height) * RYCoord);

  if fDown then
  begin

    Move := 'move';

    Form1.ServerSocket1.Socket.Connections[Index].SendText(format('mouseswipescreen%d<|>%d<|>%s'#13#10, [fPO.X, fPO.Y, Move]));

    fPO := Point(XTouch, YTouch);

  end;

end;

procedure TForm2.Image1MouseUp(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);
begin
  if fDown then
    fDown := false;
end;

的专家认为我正在构建恶意软件而不是帮助这些人。

---

回答：

我的方法是正确的，不幸的是，直到这一刻看到，不可能使用AccessibilityService实现这个目标，因为存在AccessibilityService，limitation on storage of gestures是官方参考：

here

而且，直到现在（在这种情况下）当执行2个快速鼠标点击并且发送时，addStroke(new GestureDescription.StrokeDescription(path, 0, time)); 无法在某些点（构成密码屏幕的9个点）执行触摸“仅按下并且不松动”的手势：

AccessibilityService

在开始之前和绘制密码期间（拖动鼠标），仅在完全绘制密码时释放，并且：

procedure TForm2.Image1MouseDown(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);

被发送到远程设备。

---

编辑：

注意：

procedure TForm2.Image1MouseUp(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);

能够这样做因为使用Team View QuickSupport。