如何将嵌套列表除以int 2

Question

d = [[5,3,2]，[5,1,9]，[6,8,3]]

我需要将此嵌套列表除以'2'

我尝试过的代码。

m = []

jj = 2for k,v in zip(d,jj):

m.append([k2/v2 for k2,v2 in zip(k,v)])

print(m)

所以输出可能像下面这样

d=[[2.5,1.5,1],[2.5,0.5,4.5],[3,4,1.5]

Answer 1

d=[[5,3,2],[5,1,9],[6,8,3]]
result = [[j/2 for j in i] for i in d]
print(result)