我一直在尝试创建一个正则表达式模式,匹配任何Excel公式中的任何引用,包括绝对,相对和外部引用。我需要返回整个引用,包括工作表和工作簿名称。
我无法找到有关Excel A1表示法的详尽文档,但经过大量测试后我确定了以下内容:
=A1&"A1"
会破坏正则表达式=Sheet1!A1
成功=[Book1.xlsx]Sheet1!A1
括起来'C:\[Book1.xlsx]Sheet1'!A1
的括号左侧='[Book 1.xlsx]Sheet 1'!A1
Range.Formula
仍会以A1表示法返回引用。 Range.FormulaR1C1
返回R1C1表示法中的引用。=SUM([Book5]Sheet1:Sheet3!A1)
上使用一系列工作表名称以下是我提出的用于测试的VBA程序。我更新了代码以处理名称:
Sub ReturnFormulaReferences()
Dim objRegExp As New VBScript_RegExp_55.RegExp
Dim objCell As Range
Dim objStringMatches As Object
Dim objReferenceMatches As Object
Dim objMatch As Object
Dim intReferenceCount As Integer
Dim intIndex As Integer
Dim booIsReference As Boolean
Dim objName As Name
Dim booNameFound As Boolean
With objRegExp
.MultiLine = True
.Global = True
.IgnoreCase = True
End With
For Each objCell In Selection.Cells
If Left(objCell.Formula, 1) = "=" Then
objRegExp.Pattern = "\"".*\"""
Set objStringMatches = objRegExp.Execute(objCell.Formula)
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\!)?" _
& "(\$?[a-z]{1,3}\$?[0-9]{1,7}(\:\$?[a-z]{1,3}\$?[0-9]{1,7})?" _
& "|\$[a-z]{1,3}\:\$[a-z]{1,3}" _
& "|[a-z]{1,3}\:[a-z]{1,3}" _
& "|\$[0-9]{1,7}\:\$[0-9]{1,7}" _
& "|[0-9]{1,7}\:[0-9]{1,7}" _
& "|[a-z_\\][a-z0-9_\.]{0,254})"
Set objReferenceMatches = objRegExp.Execute(objCell.Formula)
intReferenceCount = 0
For Each objMatch In objReferenceMatches
intReferenceCount = intReferenceCount + 1
Next
Debug.Print objCell.Formula
For intIndex = intReferenceCount - 1 To 0 Step -1
booIsReference = True
For Each objMatch In objStringMatches
If objReferenceMatches(intIndex).FirstIndex > objMatch.FirstIndex _
And objReferenceMatches(intIndex).FirstIndex < objMatch.FirstIndex + objMatch.Length Then
booIsReference = False
Exit For
End If
Next
If booIsReference Then
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\!)?" _
& "(\$?[a-z]{1,3}\$?[0-9]{1,7}(\:\$?[a-z]{1,3}\$?[0-9]{1,7})?" _
& "|\$[a-z]{1,3}\:\$[a-z]{1,3}" _
& "|[a-z]{1,3}\:[a-z]{1,3}" _
& "|\$[0-9]{1,7}\:\$[0-9]{1,7}" _
& "|[0-9]{1,7}\:[0-9]{1,7})"
If Not objRegExp.Test(objReferenceMatches(intIndex).Value) Then 'reference is not A1
objRegExp.Pattern = "^(\'.*(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\!)" _
& "[a-z_\\][a-z0-9_\.]{0,254}$"
If Not objRegExp.Test(objReferenceMatches(intIndex).Value) Then 'name is not external
booNameFound = False
For Each objName In objCell.Worksheet.Parent.Names
If objReferenceMatches(intIndex).Value = objName.Name Then
booNameFound = True
Exit For
End If
Next
If Not booNameFound Then
objRegExp.Pattern = "^(\'.*(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\\/\?\*\[\]]{1,31}\:)?[^\:\\\/\?\*\[\]]{1,31}\!)"
For Each objName In objCell.Worksheet.Names
If objReferenceMatches(intIndex).Value = objRegExp.Replace(objName.Name, "") Then
booNameFound = True
Exit For
End If
Next
End If
booIsReference = booNameFound
End If
End If
End If
If booIsReference Then
Debug.Print " " & objReferenceMatches(intIndex).Value _
& " (" & objReferenceMatches(intIndex).FirstIndex & ", " _
& objReferenceMatches(intIndex).Length & ")"
End If
Next intIndex
Debug.Print
End If
Next
Set objRegExp = Nothing
Set objStringMatches = Nothing
Set objReferenceMatches = Nothing
Set objMatch = Nothing
Set objCell = Nothing
Set objName = Nothing
End Sub
谁能打破或改善这个?如果没有关于Excel公式语法的详尽文档,很难知道这是否正确。
谢谢!
jtolle引导我朝着正确的方向前进。据我所知,这就是我试图做的事情。我一直在测试它似乎工作。
stringOriginFormula = rangeOrigin.Formula
rangeOrigin.Cut rangeDestination
rangeOrigin.Formula = stringOriginFormula
谢谢jtolle!
谢谢Ben(我很想在这里发帖,尽管Stackoverflow多年来引起了我对高质量技术的关注,所以我不确定我是否正确地为作者J阅读了这个页面)
我尝试了发布的解决方案(测试,测试更新,以及使用range.precendents(正确指出,不包括对其他工作表或其他工作簿的引用)的解决方案,并发现一个小缺陷:外部工作表名称包含在'单引号'只有在它是一个数字时;如果它包含空格(可能还有其他字符如Ben(?)在原始帖子中列出。只需加上regEx(开[],就可以更正(添加“ [“,请参阅下面的代码。)此外,为了我自己的目的,我将sub转换为一个函数,它将返回一个逗号分隔的列表,删除重复项(注意,这将删除相同的引用符号,而不是包含在多个中的单元格范围):
Public Function CellReflist(Optional r As Range) ' single cell
Dim result As Object: Dim testExpression As String: Dim objRegEx As Object
If r Is Nothing Then Set r = ActiveCell ' Cells(1, 2) ' INPUT THE CELL HERE , e.g. RANGE("A1")
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.IgnoreCase = True: objRegEx.Global = True: objRegEx.Pattern = """.*?""" ' remove expressions
testExpression = CStr(r.Formula)
testExpression = objRegEx.Replace(testExpression, "")
'objRegEx.Pattern = "(([A-Z])+(\d)+)" 'grab the address
objRegEx.Pattern = "(['\[].*?['!])?([[A-Z0-9_]+[!])?(\$?[A-Z]+\$?(\d)+(:\$?[A-Z]+\$?(\d)+)?|\$?[A-Z]+:\$?[A-Z]+|(\$?[A-Z]+\$?(\d)+))"
If objRegEx.Test(testExpression) Then
Set result = objRegEx.Execute(testExpression)
If result.Count > 0 Then CellReflist = result(0).Value
If result.Count > 1 Then
For i = 1 To result.Count - 1 'Each Match In result
dbl = False ' poistetaan tuplaesiintymiset
For j = 0 To i - 1
If result(i).Value = result(j).Value Then dbl = True
Next j
If Not dbl Then CellReflist = CellReflist & "," & result(i).Value 'Match.Value
Next i 'Match
End If
End If
结束功能