按两列对HTML表进行排序

问题描述 投票：1回答：2

我在表格中有几列，例如A，B，C，D和E列，我需要在HTML页面中显示。在某些页面中，我需要仅根据页面的一列显示排序结果，例如列“C”（表格的第3列）。我可以使用以下代码执行此操作：

function Ascending(a, b) {
  if (a < b) return -1;
  if (a > b) return 1;
  return 0;
}
var rows = $('#table tr').not(':first').get();
$('#table tr').slice(1).remove();
rows.sort(function(rowA, rowB) {
  var keyA = $(rowA).children('td').eq(2).text().toUpperCase();
  var keyB = $(rowB).children('td').eq(2).text().toUpperCase();
  return Ascending(keyA, keyB);
});

但我有另一个要求，其中我需要根据两列显示排序结果，即在上述情况下基于列C的排序，列E的结果也应该被排序。例如：

排序前：

Column C  Column E
2         Fish
1         Box
7         Cat
2         Dog
1         Apple
2         Box
2         Axe
7         Box
2         Answer
7         Apple
6         Year
2         Goat

仅排序C列后：

Column C  Column E
1         Box
1         Apple
2         Dog
2         Fish
2         Box
2         Axe
2         Goat
2         Answer
6         Year
7         Box
7         Apple
7         Cat

排序C列然后排E列：

Column C  Column E
1         Apple
1         Box
2         Answer
2         Axe
2         Box
2         Dog
2         Fish
2         Goat
6         Year
7         Apple
7         Box
7         Cat

我无法实施。我该怎么做？

javascript jquery html sorting
2个回答
8
投票

要按多列排序，您可以像这样编写比较函数：

（比较函数传递两个“行”）

  1. 将第1行第1列与第2列第1列进行比较 如果它们不同则返回结果（a + ve或-ve数）
  2. 将第1行第2列与第2列第2列进行比较 如果它们不同则返回结果（a + ve或-ve数）
  3. 重复其余列
  4. 返回0

以下示例显示如何编写按两列排序的比较函数。可以使用循环或递归来按n列排序。

$(function() {
  function sortByColumn3(row1, row2) {
    var v1, v2;
    v1 = $(row1).find("td:eq(2)").text();
    v2 = $(row2).find("td:eq(2)").text();
    // for numbers you can simply return a-b instead of checking greater/smaller/equal
    return v1 - v2;
  }

  function sortByColumn3And5(row1, row2) {
    var v1, v2, r;
    v1 = $(row1).find("td:eq(2)").text();
    v2 = $(row2).find("td:eq(2)").text();
    r = v1 - v2;
    if (r === 0) {
      // we have a tie in column 1 values, compare column 2 instead
      v1 = $(row1).find("td:eq(4)").text();
      v2 = $(row2).find("td:eq(4)").text();
      if (v1 < v2) {
        r = -1;
      } else if (v1 > v2) {
        r = 1;
      } else {
        r = 0;
      }
    }
    return r;
  }
  $("#button1, #button2").on("click", function() {
    var rows = $("#table1 tbody tr").detach().get();
    switch (this.id) {
      case "button1":
        rows.sort(sortByColumn3);
        break;
      case "button2":
        rows.sort(sortByColumn3And5);
        break;
    }
    $("#table1 tbody").append(rows);
  });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>

<input type="button" id="button1" value="sortByColumn3">
<input type="button" id="button2" value="sortByColumn3And5">

<table id="table1" border="1" width="100%">
  <thead>
    <tr>
      <td>1</td>
      <td>2</td>
      <td>3</td>
      <td>4</td>
      <td>5</td>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td>x</td>
      <td>y</td>
      <td>2</td>
      <td>z</td>
      <td>Fish</td>
    </tr>
    <tr>
      <td>y</td>
      <td>z</td>
      <td>1</td>
      <td>x</td>
      <td>Box</td>
    </tr>
    <tr>
      <td>z</td>
      <td>x</td>
      <td>7</td>
      <td>y</td>
      <td>Cat</td>
    </tr>
    <tr>
      <td>x</td>
      <td>y</td>
      <td>2</td>
      <td>z</td>
      <td>Dog</td>
    </tr>
    <tr>
      <td>y</td>
      <td>z</td>
      <td>1</td>
      <td>x</td>
      <td>Apple</td>
    </tr>
    <tr>
      <td>z</td>
      <td>x</td>
      <td>2</td>
      <td>y</td>
      <td>Box</td>
    </tr>
    <tr>
      <td>x</td>
      <td>y</td>
      <td>2</td>
      <td>z</td>
      <td>Axe</td>
    </tr>
    <tr>
      <td>y</td>
      <td>z</td>
      <td>7</td>
      <td>x</td>
      <td>Box</td>
    </tr>
    <tr>
      <td>z</td>
      <td>x</td>
      <td>2</td>
      <td>y</td>
      <td>Answer</td>
    </tr>
    <tr>
      <td>x</td>
      <td>y</td>
      <td>7</td>
      <td>z</td>
      <td>Apple</td>
    </tr>
    <tr>
      <td>y</td>
      <td>z</td>
      <td>6</td>
      <td>x</td>
      <td>Year</td>
    </tr>
    <tr>
      <td>z</td>
      <td>x</td>
      <td>2</td>
      <td>y</td>
      <td>Goat</td>
    </tr>
  </tbody>
</table>
0
投票

function sortTable() {
    var table, rows, switching, i, x, y, a, b, shouldSwitch;
    table = document.getElementById("mytable");
    switching = true;
    while (switching) {
        switching = false;
        rows = table.getElementsByTagName("TR");
        for (i = 0; i < (rows.length - 1); i++) {
            shouldSwitch = false;
            /*Get the two elements you want to compare,
            one from current row and one from the next:*/
            x = rows[i].getElementsByTagName("TD")[3];
            y = rows[i + 1].getElementsByTagName("TD")[3];
            //check if the two rows should switch place:
            if (Number(x.innerHTML) < Number(y.innerHTML)) {
                //if so, mark as a switch and break the loop:
                shouldSwitch = true;
                break;
            }


        }
        if (shouldSwitch) {
            /*If a switch has been marked, make the switchcand mark that a switch has been done:*/
            rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
            switching = true;
        }
    }
  
    for (i = 0; i < (rows.length - 1); i++) {
        /*Get the two elements you want to compare,one from current row and one from the next:*/
        for (j = i + 1; j < (rows.length); j++) {
            x = rows[i].getElementsByTagName("TD")[3];
            y = rows[j].getElementsByTagName("TD")[3];
            a = rows[i].getElementsByTagName("TD")[0];
            b = rows[j].getElementsByTagName("TD")[0];
            //check if the two rows should switch place:
            if (Number(x.innerHTML) == Number(y.innerHTML)) {
                //if so, swap
                if (Number(a.innerHTML) > Number(b.innerHTML)) {
                    rows[i].parentNode.insertBefore(rows[j], rows[i]);

                }
            }
        }
    }
}
<body>
<div class="container">
  <form class="form-horizontal" role="form">
    <div class="form-group">
      <button id="sort" onclick="sortTable()" type="button" class="btn btn-default">sort</button>
    </div>
  </form>

  <div class="contents">
    <table class="table">
      <thead>
        <tr>
          <th>Id</th>
          <th>Image</th>
          <th>Name</th>
          <th>Price</th>
        </tr>
      </thead>
     <tbody id="mytable"><tr><td>5</td><td><img src="image/5.gif"></td><td>cony #5</td><td>170</td></tr><tr><td>1</td><td><img src="image/1.gif"></td><td>cony #1</td><td>170</td></tr><tr><td>2</td><td><img src="image/2.gif"></td><td>cony #2</td><td>270</td></tr><tr><td>8</td><td><img src="image/8.gif"></td><td>cony #8</td><td>70</td></tr><tr><td>10</td><td><img src="image/10.gif"></td><td>cony #10</td><td>170</td></tr><tr><td>4</td><td><img src="image/4.gif"></td><td>cony #4</td><td>150</td></tr><tr><td>3</td><td><img src="image/3.gif"></td><td>cony #3</td><td>130</td></tr><tr><td>6</td><td><img src="image/6.gif"></td><td>cony #6</td><td>160</td></tr><tr><td>9</td><td><img src="image/9.gif"></td><td>cony #9</td><td>170</td></tr><tr><td>7</td><td><img src="image/7.gif"></td><td>cony #7</td><td>170</td></tr></tbody>
   
    </table>
  </div>
</div>
</body>

Javascript中的简单解决方案如果相同的价格列ID将按升序排列，则上面的示例按价格的降序排列

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