带有Expression的EF LINQ查询:期望的方法名称 - 如何将表达式传递给要在EF查询中使用的函数?

问题描述 投票:1回答:1

我有一个函数,它应该根据传递给它的Expression和/或lambda从EF LINQ查询中返回不同的信息。

这是我的代码:

public static ObservableCollection<SI> GetDisplayStratsByJurisd(string jurisd, short Year, 
      Expression<Func<string, bool>> lambStat)
    {
        var ctx = new MI_Entities(server, database);

        var strats = from y in ctx.SIset.AsNoTracking()
                     where y.Jurisd == jurisd && y.Year_ID == Year  && lambStat(y.Status)
                     select y;
        return new ObservableCollection<SI>(strats);
    }

编译器给我以下错误:

预期的方法名称

如果我改用它:

    public static ObservableCollection<SI> GetDisplayStratsByJurisd(string jurisd, short Year, 
      Expression<Func<string, bool>> lambStat)
    {
        var ctx = new MI_Entities(server, database);
        Func<string, bool> bob = lambStat.Compile();
        var strats = from y in ctx.SIset.AsNoTracking()
                     where y.Jurisd == jurisd && y.Year_ID == Year  && bob(y.Status)
                     select y;
        return new ObservableCollection<SI>(strats);
    }

然后我得到一个不同的错误:

LINQ to Entities不支持LINQ表达式节点类型“Invoke”

所以,我不确定如何将lambda传递给函数,以便可以在查询中使用它。可以这样做吗?如果是这样,怎么样?

c# entity-framework linq-to-entities
1个回答
1
投票

所以你有一些Expression<Func<TSource, bool>>,并且你想使用AND功能将它们组合成一个Expression<Func<TSource, bool>>,这样你就可以在实体框架中使用它AsQueryable。

以LINQ之类的方式使用它会很好,所以我们可以将它放在Linq语句的串联之间。

让我们创建一些扩展函数。

// A function that takes two Expression<Func<TSource, bool>> and returns the AND expression
static Expression<Func<TSource, bool>> AndAlso<TSource> (
    this Expression<Func<TSource, bool>> x,
    Expression<Func<TSource, bool>> y)
{
     // TODO implement
}

用法:

 Expression<Func<Student, bool>> expr1 = student => student.City == "Birmingham";
 Expression<Func<Student, bool>> expr2 = student => student.Gender == Gender.Male;
 Expression<Func<Student, bool>> exprAND = expr1.AndAlso(expr2);

 var brummyMaleStudents = dbContext.Students.Where(exprAnd).Select(...);

让我们实现AndAlso

通常情况下会是这样的:

.Where(student  => student.City == "Birmingham" && student.Gender == Gender.Male)

输入参数student用作左表达式的输入和右​​表达式的输入。我们需要有一些说法:

取一个Student类型的输入参数,将其放在左表达式中,并在右表达式中,并在两个布尔返回值之间执行AND。返回布尔结果。

为此,我们创建了一个派生自System.Linq.Expressions.ExpressionVisitor的类。

此类表示操作:“将学生放入表达式并计算它”。该计算称为“访问表达式”。表达式的输入是一个表达式,访问的结果是另一个表达式:

internal class ReplaceExpressionVisitor : ExpressionVisitor
{
    private readonly Expression oldValue;
    private readonly Expression newValue;

    public ReplaceExpressionVisitor(ParameterExpression oldValue,
                                    ParameterExpression newValue)
    {
        this.oldValue = oldValue;
        this.newValue = newValue;
    }

    public override Expression Visit(Expression node)
    {
        if (node == this.oldValue)
        {   // "my" expression is visited
            return this.newValue;
        }
        else
        {   // not my Expression, I don't know how to Visit it, let the base class handle this
            return base.Visit(node);
        }
    }
}

现在我们已经创建了表达式访问者,我们可以实现AndAlso:

static Expression<Func<TSource, bool>> AndAlso<TSource>(
    this Expression<Func<TSource, bool>> expr1,
         Expression<Func<TSource, bool>> expr2)
{
     // Create one expression that represent expr1 && expr2
     // the input of expr1 is a TSource,
     // the input of expr2 is a TSource,
     // so the input of expr1 && expr2 is a TSource:
     ParameterExpression inputParameter = Expression.Parameter(typeof(TSource));

     // Visit the left part of the AND:
     var leftVisitor = new ReplaceExpressionVisitor(expr1.Parameters[0], inputParameter)
     var left = leftVisitor.Visit(expr1.Body);

     // Visit the right part of the AND:
     var rightVisitor = new ReplaceExpressionVisitor(expr2.Parameters[0], parameter);
     var right = rightVisitor.Visit(expr2.Body);

     // Combine left and right with a binary expression representing left && right:
     var andExpression = Expression.AndAlso(left, right);

     // return the lambda expression that takes one Tsource as input and returns the AND:
     var lambda = Expression.Lambda<Func<TSource, bool>>(andExpression, new[] {parameter});
     return lambda;
}

用法:

 Expression<Func<Student, bool>> expr1 = student => student.City == "Birmingham";
 Expression<Func<Student, bool>> expr2 = student => student.Gender == Gender.Male;

 var brummyMaleStudents = dbContext.Students.Where(expr1.AndAlso(expr2));
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