如何检查用户输入是否为整数

Question

我想编写一个代码，如果用户在显示的菜单中输入任何无效选项，它会要求用户输入有效选项，在本例中是整数 1-7。

但是这里无论用户输入什么选项，都会显示这是一个无效的选择。

def update_profile():
        while True:
            print("Choose the options below to update the info")
            print("1.Username\n2.Password\n3.Email\n4.Date of Birth\n5.Address\n6.Contact Number\n7.Exit")
            choice = input("Enter your choice:")

            try:
                int(choice)
            except ValueError:
                pass

            match choice:
                case 1:
                   ...
                case 2:
                   ...
                case _:
                   print("Invalid choice. Please select again.")
                   print("--------------------------------------------")
                   continue
            repeat = input("Do you want to continue update the profile? <Yes [Y]\tNo [N]>\nYour choice: ")
            if repeat == 'N' or repeat == 'n':
                break  

输出：

Choose the options below to update the info
1.Username
2.Password
3.Email
4.Date of Birth
5.Address
6.Contact Number
7.Exit
Enter your choice:1
Invalid choice. Please select again.
--------------------------------------------
Choose the options below to update the info
1.Username
2.Password
3.Email
4.Date of Birth
5.Address
6.Contact Number
7.Exit
Enter your choice:

Answer 1

int() 不会更改其参数值，而是返回结果。 因此，在异常处理块中，您可以分配一个新变量并将其用于匹配块。

def update_profile():
while True:
    print("Choose the options below to update the info")
    print("1.Username\n2.Password\n3.Email\n4.Date of Birth\n5.Address\n6.Contact Number\n7.Exit")
    choice = input("Enter your choice:")
    try:
        choice_int = int(choice)
    except ValueError as e:
        print(e)
        pass

    match choice_int:
        case 1:
            ...
        case 2:
            ...
        case _:
            print("Invalid choice. Please select again.")
            print("--------------------------------------------")
            continue
    repeat = input("Do you want to continue update the profile? <Yes [Y]\tNo [N]>\nYour choice: ")
    if repeat == 'N' or repeat == 'n':
        break