我有以下文件(app.py
),该文件生成Flask
实例并定义一些路由并声明/初始化简单形式:
from flask import Flask, render_template, url_for
from flask_wtf import FlaskForm
import wtforms as wtf
from wtforms.fields.html5 import DecimalRangeField
app = Flask(__name__)
app.config['SECRET_KEY'] = 'youll-never-guess'
class Form(FlaskForm):
age = DecimalRangeField('age', default=30)
submit = wtf.SubmitField('submit')
@app.route('/form/', methods=['GET'])
def form():
form = Form()
return render_template('form.html', form=form)
@app.route('/form/submit/', methods=['POST'])
def submit_form():
return 'form submitted!'
def main():
app.run(debug=True, port=5000)
if __name__ == '__main__':
main()
templates/form.html
文件如下:
<form id="form" action="{{ url_for('submit_form') }}" method="POST" onchange="submitForm(this);">
{% for field in form %}
{{ field }}
{% endfor %}
</form>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>
function submitForm(form) {
console.log(`submitting form ${form} ... `);
$(form).submit();
}
</script>
当我更改滑块时,控制台会打印submitting form [object HTMLFormElement] ...
,但似乎没有调用视图功能submit_form
。但是,当我单击submit
按钮时,/form/submit/
URL会显示为文本form submitted!
。 为什么请这样?
class Form(FlaskForm):
age = DecimalRangeField('age', default=30)
sub = wtf.SubmitField('sub')
或者,您可以直接在模板中添加表单按钮,但是它既没有ID,也没有名称submit
。
this
指代当前的回调函数作用域,它没有任何submit
方法。因此,请使用JQuery或香草JS如下获取表单对象:
var form = document.getElementById("form");
$(form).submit();