我正在将一些遗留的Objective-C代码翻译成Swift。在这里,我正在努力处理一些URL方案。
应用程序委托中的以下Objective-C代码返回外部应用程序的ID,它通过URL方案发送消息:
- (BOOL)application:(UIApplication *)app openURL:(NSURL *)url
options:(NSDictionary<UIApplicationOpenURLOptionsKey,id> *)options {
NSString *appName = [options valueForKey:@"UIApplicationOpenURLOptionsSourceApplicationKey"];
NSString *urlVal = [url absoluteString];
NSLog(@"external url scheme call from app %@: %@", appName, urlVal);
return TRUE;
}
在Swift中,存在相同的方法,但在选项字典中,不再有关于发送应用程序的信息。而且,我无法打印外国应用程序的id:
func application(_ app: UIApplication, open url: URL,
options: [UIApplication.OpenURLOptionsKey : Any] = [:]) -> Bool {
let appName = options[.sourceApplication]
let urlVal = url.absoluteString
NSLog("external url scheme call from %@: %@", appName, urlVal)
return true
}
所以问题是:如何在上述方法的Swifts实现中获取发送应用程序的ID?
以下是您问题的确切答案。检查此密钥options[.sourceApplication]
。
// --------- OPEN APP WITH URL -----------
func application(_ application: UIApplication,
open url: URL,
options: [UIApplication.OpenURLOptionsKey : Any] = [:] ) -> Bool {
// Determine who sent the URL.
let sendingAppID = options[.sourceApplication]
print("source application = \(sendingAppID ?? "Unknown")")
if let string = sendingAppID as? String, string == "com.apple.springboard" {
if let components = url.queryCryptoenterDict {
qRcode(dictionary: components)
}
return true // just to quit from function
}
}
其中qRcode(:)
是我的QR码处理程序。
问题出在Swift的NSLog
上。使用源应用程序的debugDescription属性修复了问题:
func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any] = [:]) -> Bool {
let appName = options[.sourceApplication].debugDescription
let urlVal = url.absoluteString
NSLog("external url scheme call from %@: %@", appName, urlVal)
return true
}