我如何对字节文件的单词袋进行自定义实现？

Question

我正在尝试对字节文件中存在的十六进制代码进行词袋的自定义实现。因此，十六进制语料库将由“？”之类的字符组成。我发现此代码可用于Bow的自定义实现，但它删除了“ ??”来自语料库。

# Replace all none alphanumeric characters with spaces
s="0,1,2,3,4,5,6,7,8,9,0a,0b,0c,0d,0e,0f,10,11,12,13,14,15,16,17,18,19,1a,1b,1c,1d,1e,1f,20,21,22,23,24,25,26,27,28,29,2a,2b,2c,2d,2e,2f,30,31,32,33,34,35,36,37,38,39,3a,3b,3c,3d,3e,3f,40,41,42,43,44,45,46,47,48,49,4a,4b,4c,4d,4e,4f,50,51,52,53,54,55,56,57,58,59,5a,5b,5c,5d,5e,5f,60,61,62,63,64,65,66,67,68,69,6a,6b,6c,6d,6e,6f,70,71,72,73,74,75,76,77,78,79,7a,7b,7c,7d,7e,7f,80,81,82,83,84,85,86,87,88,89,8a,8b,8c,8d,8e,8f,90,91,92,93,94,95,96,97,98,99,9a,9b,9c,9d,9e,9f,a0,a1,a2,a3,a4,a5,a6,a7,a8,a9,aa,ab,ac,ad,ae,af,b0,b1,b2,b3,b4,b5,b6,b7,b8,b9,ba,bb,bc,bd,be,bf,c0,c1,c2,c3,c4,c5,c6,c7,c8,c9,ca,cb,cc,cd,ce,cf,d0,d1,d2,d3,d4,d5,d6,d7,d8,d9,da,db,dc,dd,de,df,e0,e1,e2,e3,e4,e5,e6,e7,e8,e9,ea,eb,ec,ed,ee,ef,f0,f1,f2,f3,f4,f5,f6,f7,f8,f9,fa,fb,fc,fd,fe,ff,??"

import re

def generate_ngrams(s, n):
    # Convert to lowercases
    s = s.lower()

    s = re.sub(r'[^a-zA-Z0-9\s]', ' ', s)

    # Break sentence in the token, remove empty tokens
    tokens = [token for token in s.split(" ") if token != ""]

    # Use the zip function to help us generate n-grams
    # Concatentate the tokens into ngrams and return
    ngrams = zip(*[token[i:] for i in range(n)])
    return [" ".join(ngram) for ngram in ngrams]

在删除此行：s = re.sub(r'[^a-zA-Z0-9\s]', ' ', s)时，不返回任何内容

Answer 1

正则表达式用单个空格替换not的每个字符（a-z，A-Z，0-9，任何空白）。其中包括您要保留的?。将其添加到排除集中

s = re.sub(r'[^a-zA-Z0-9\s?]', ' ', s)

要使其正常工作（您还必须修复token中的错别字）。

如果删除正则表达式，它不返回任何内容的原因是因为它仅在spaces上分割-在原始字符串中不包含任何内容-然后返回每个pair个单词。您无法用单个物品配对。