Google表单“无法将[对象对象]转换为（类）”

Question

大家早上好。我需要你的帮助。我需要运行此脚本来删除Google答复表单中的重复项

我将此代码复制到电子表格中，因为它直接以TypeError形式给我此错误：无法调用null的“ getSheetByName”方法。 （第16行，文件“ UPDATEcontact”）：

function updateExisting(columnWithUniqueIdentifier,sheetTabName) {
  var dataFromColumnToMatch,lastColumn,lastRow,rowWithExistingUniqueValue,rowOfDataJustSaved,
      sh,ss,valueToSearchFor;

  // USER SETTINGS - if the values where not passed in to the function
  if (!columnWithUniqueIdentifier) {//If you are not passing in the column number
    columnWithUniqueIdentifier = 2;//Hard code column number if you want
  }

  if (!sheetTabName) {//The sheet tab name was not passed in to the function
    sheetTabName = "compleanno2020";//Hard code if needed
  }
  //end of user settings

  ss = SpreadsheetApp.getActiveSpreadsheet();//Get the active spreadsheet - this code must be in a project bound to spreadsheet
  sh = ss.getSheetByName(sheetTabName);


  lastRow = sh.getLastRow();
  lastColumn = sh.getLastColumn();

  //Logger.log('lastRow: ' + lastRow)

  rowOfDataJustSaved = sh.getRange(lastRow, 1, 1, lastColumn).getValues();//Get the values that were just saved

  valueToSearchFor = rowOfDataJustSaved[0][columnWithUniqueIdentifier-1];
  //Logger.log('valueToSearchFor: ' + valueToSearchFor)

  dataFromColumnToMatch = sh.getRange(1, columnWithUniqueIdentifier, lastRow-1, 1).getValues();
  dataFromColumnToMatch = dataFromColumnToMatch.toString().split(",");
  //Logger.log('dataFromColumnToMatch: ' + dataFromColumnToMatch)

  rowWithExistingUniqueValue = dataFromColumnToMatch.indexOf(valueToSearchFor);
  //Logger.log('rowWithExistingUniqueValue: ' + rowWithExistingUniqueValue)

  if (rowWithExistingUniqueValue === -1) {//There is no existing data with the unique identifier
    return;
  }

  sh.getRange(rowWithExistingUniqueValue + 1, 1, 1, rowOfDataJustSaved[0].length).setValues(rowOfDataJustSaved);
  sh.deleteRow(lastRow);//delete the row that was at then end
}

现在我有这个问题。

如果我单击一下即可启动宏，则一切正常。

[如果将宏与触发器关联，则会收到此错误消息：无法将[object Object]转换为（class）。在updateExisting（未重复：29）

这是我的电子表格：

我该如何解决这个问题？非常感谢大家。

Answer 1

open(file)

open(file)
• openById(id)