如何让CPU在这个python nims游戏中占用适量的棒子

Question

import random

def print_move(current_player,row,stick_quantity):
  current_player = current_player
  print(f"{current_player} takes {stick_quantity} sticks from {row} row")

 
sticks = [1, 3, 5, 7]

def nims():
  for count, stick in enumerate(sticks):
    print(count+1,stick * "|")


print("Welcome to Nim!")
name = input("Enter name: ")
current_player = random.choice([name, "CPU"])
print('game is starting',(current_player),'will be going first')
 
while True:
  if current_player == name:
    row = int(input("Which row would you like to take sticks from? "))
    stick_quantity = int(input("How many sticks would you like to take? "))
    sticks[row - 1] -= stick_quantity    
    print_move(current_player,row,stick_quantity)
    if current_player == name:
      current_player = "CPU"
    else:
      current_player = name
  
  elif current_player == "CPU":
    row = random.choice([1,2,3,4])
    stick_quantity = random.choice([1,2,3,4,5,6,7])
    sticks[row - 1] -= stick_quantity
    print_move(current_player,row,stick_quantity)
    if current_player == "CPU":
      current_player = name
    else:
      current_player = "CPU"


  nims()

在我创建的 nims 游戏中，我创建了一个 CPU，它可以从一定数量的行中移除一定数量的木棍。我已经做到了这一点，所以它是一个随机选择，但我遇到了这个问题，CPU 将决定从棍棒已经消失的行中取出大量棍棒。我希望CPU只能获取适量的木棍，并且如果CPU从一行中移除大量的木棍，而木棍不在那里，我想要一个循环，直到CPU占用适量的木棍。

Answer 1

您可以添加 CPU 控件，以检查所选行中是否有足够的可用内存条。如果没有，CPU 应选择不同的行或选择较少数量的棒。

基本上，CPU 行为可以设计如下：

def cpu_turn():
    while True:
        row = random.randint(1, len(sticks))
        if sticks[row - 1] > 0:
            max_sticks = min(sticks[row - 1], 7)  # Maximum sticks CPU can take
            stick_quantity = random.randint(1, max_sticks)
            sticks[row - 1] -= stick_quantity
            print_move(current_player, row, stick_quantity)
            break

然后：

elif current_player == "CPU":
   cpu_turn()
   if current_player == "CPU":
      current_player = name
   else:
      current_player = "CPU"